html制作迷宫_html/css_WEB-ITnose
- WBOY원래의
- 2016-06-24 11:39:281577검색
大神求帮助 如何用HTML制作出如图的迷宫
回复讨论(解决方案)
方法很多，canvas、svg画图，也可以用表格、div去掉一部分的边框（不过这种CSS要写的很多）。
我走出来了
具体 用表格和div怎么做，用css怎么去掉边框
你是要用于展示还是想在网页上做一个迷宫出来，让人能走？
前者的话，把图片贴上去就行了。
后者的话，用canvas+JS做。
<!doctype html><html lang="en"><head> <meta charset="UTF-8"> <title> 页面名称 </title><style type="text/css">#map { width: 124px; height: 124px;}#map div { width: 30px; height: 30px; float: left; border: 1px solid transparent; margin: 0px -1px -1px 0px;}#map .l {border-left: 1px solid #000;}#map .r {border-right: 1px solid #000;}#map .t {border-top: 1px solid #000;}#map .b {border-bottom: 1px solid #000;}</style></head><body><div id="map"> <div class="l t"></div> <div class="l"></div> <div class="t"></div> <div class="t r"></div> <div class="l"></div> <div class="t"></div> <div class="t l"></div> <div class="r"></div> <div class="l"></div> <div class="t"></div> <div class=""></div> <div class="l t r"></div> <div class="l t b"></div> <div class="b"></div> <div class="t b"></div> <div class="r b"></div></div> </body></html> Jsoup
Document doc1 = Jsoup.connect("http://www.paperyy.com/").get();
以下是一个 perfect 型迷宫的生成代码, 在边缘任取两处分别作为入口和出口即可
<!DOCTYPE html><html> <head> <style> #myCanvas{ border:1px solid #d3d3d3; } </style> </head> <body> <canvas id="myCanvas" width=800 height=600 > Your browser does not support the HTML5 canvas tag. </canvas> </body></html><script> var canv = document.getElementById("myCanvas"); var cell_width = cell_height = 10; var edge_blank = cell_width; var clear_width = cell_width * 2 - 2; var clear_height = cell_height * 2 - 2; // 最大逻辑坐标, 坐标起始于 0, 终于 xe, ye var xe = Math.floor(canv.width / cell_width - 2); var ye = Math.floor(canv.height / cell_height - 2); var ctx = canv.getContext("2d"); ctx.beginPath(); var x_end = edge_blank + (xe - 1) * cell_width; y_end = edge_blank + (ye - 1) * cell_height; for (var y = edge_blank + cell_height; y <= y_end; y += 2 * cell_height) { ctx.moveTo(edge_blank + cell_width, y); ctx.lineTo(x_end, y); } for (var x = edge_blank + cell_width; x <= x_end; x += 2 * cell_width) { ctx.moveTo(x, edge_blank + cell_height); ctx.lineTo(x, y_end); } ctx.strokeStyle = "black"; ctx.stroke(); var maze = Array(xe + 1); for (var i = 0; i <= xe; i++) { maze[i] = Array(ye + 1); for (var j = 0; j <= ye; j++) { maze[i][j] = {road: false, gen: false}; } } var dirs = [], cells = []; var x = y = 2; var item_last, dir, visit, randS, randE, dc; while (true) { if (maze[x][y].gen) { if (dirs[dirs.length - 1] == 0xf) { dirs.pop(); cells.pop(); if (cells.length == 0) { // alert('Maze generation completed'); break; } item_last = cells[cells.length - 1]; x = item_last.x; y = item_last.y; } else { item_last = cells[cells.length - 1]; x = item_last.x; y = item_last.y; dir = dirs[dirs.length - 1]; visit = 1; randS = Math.round(Math.random() * 3); randE = randS | 4; for (var i = randS; i < randE; i++) { if (visit != 0) { dc = 1 << (i & 3); visit = dir & dc; dir |= dc; if (visit == 0) { switch (dc) { case 1: y -= 2; break; case 2: x -= 2; break; case 4: x += 2; break; case 8: y += 2; break; } dirs[dirs.length - 1] = dir; // dirs.pop(); dirs.push(dir); } } } } } else { // 可通行点 if (!(0 < x && x < xe && 0 < y && y < ye)) { item_last = cells[cells.length - 1]; x = item_last.x; y = item_last.y; } else { cells.push({x: x, y: y}); maze[x][y].gen = true; for (var i = 0; i < 2; i++) { maze[x][y].road = true; ctx.clearRect(edge_blank + (x - 1) * cell_width + 1, edge_blank + (y - 1) * cell_height + 1, clear_width, clear_height); switch (dc) { case 1: y += 1; break; case 2: x += 1; break; case 4: x -= 1; break; case 8: y -= 1; break; } } switch (dc) { case 1: y -= 2; break; case 2: x -= 2; break; case 4: x += 2; break; case 8: y += 2; break; } dc = 1 << Math.round(Math.random() * 3); dirs.push(dc); switch (dc) { case 1: y -= 2; break; case 2: x -= 2; break; case 4: x += 2; break; case 8: y += 2; break; } } } }</script> 성명：
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