mysql_query()不能正常解析sql
- WBOY원래의
- 2016-06-23 13:57:02983검색
一个sql语句，直接放到mysql里运行是正常的
但用php的mysql_query运行该sql后结果却不同，会是mysql_query不能解析的原因吗？
sql如下：
INSERT INTO analysis.caomei_of_list_pvuv (region,isp,uv,pv,date) SELECT tb2.region,tb2.isp,tb2.uv,tb2.pv,'2014-05-14' AS date FROM ( SELECT tb.region,tb.isp, COUNT(tb.mac) AS uv, SUM(tb.mac_num) AS pv FROM caomei_20140515.caomei_1 AS tb WHERE tb.date = '2014-05-14' GROUP BY tb.region, tb.isp ) AS tb2 LEFT JOIN ( SELECT tb6.region,tb6.isp,tb6.uv,tb6.pv FROM analysis.caomei_of_list_pvuv AS tb6 WHERE tb6.date='2014-05-14' ) AS tb1 ON tb2.region = tb1.region WHERE tb1.region IS NULL AND tb2.region IS NOT NULL ;
回复讨论(解决方案)
NSERT INTO analysis.caomei_of_list_pvuv
(region,isp,uv,pv,date)
SELECT
tb2.region,tb2.isp,tb2.uv,tb2.pv,'2014-05-14' AS date
FROM
(
SELECT
tb.region,tb.isp, COUNT(tb.mac) AS uv,
SUM(tb.mac_num) AS pv
FROM
caomei_20140515.caomei_1 AS tb
WHERE
tb.date = '2014-05-14'
GROUP BY tb.region, tb.isp
) AS tb2
LEFT JOIN
(
SELECT
tb6.region,tb6.isp,tb6.uv,tb6.pv
FROM
analysis.caomei_of_list_pvuv AS tb6
WHERE
tb6.date='2014-05-14'
) AS tb1
ON tb2.region = tb1.region
WHERE
tb1.region IS NULL
AND tb2.region IS NOT NULL
这是不允许的
NSERT INTO analysis.caomei_of_list_pvuv
(region,isp,uv,pv,date)
SELECT
tb2.region,tb2.isp,tb2.uv,tb2.pv,'2014-05-14' AS date
FROM
(
SELECT
tb.region,tb.isp, COUNT(tb.mac) AS uv,
SUM(tb.mac_num) AS pv
FROM
caomei_20140515.caomei_1 AS tb
WHERE
tb.date = '2014-05-14'
GROUP BY tb.region, tb.isp
) AS tb2
LEFT JOIN
(
SELECT
tb6.region,tb6.isp,tb6.uv,tb6.pv
FROM
analysis.caomei_of_list_pvuv AS tb6
WHERE
tb6.date='2014-05-14'
) AS tb1
ON tb2.region = tb1.region
WHERE
tb1.region IS NULL
AND tb2.region IS NOT NULL
这是不允许的
但是mysql是能正常执行得到结果。
php也能执行，只是结果出现偏移了！！
问题不在于是否有语法错
而在于控制逻辑是循环悖论
但我觉得这样应该没有逻辑问题啊，先查出结果。然后将结果写入自己。
最主要是 php运行的结果和mysql运行的结果不同！！
是要尽量避免这种逻辑吗，否则就会出现这种意想不到的结果啊
INSERT INTO a (version)SELECT version FROM a WHERE id=1;
假定第一次执行插入了 1 条
那么第二次执行就会插入 2 条
第三次执行就会插入 4 条
我知道了。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。