>백엔드 개발 >PHP 튜토리얼 >显示数据库中blob类型的图片,小弟我图片显示不出来

显示数据库中blob类型的图片,小弟我图片显示不出来

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2016-06-13 11:26:071469검색

显示数据库中blob类型的图片,我图片显示不出来
showimage.php

<?php  <br />include_once dirname(dirname (dirname ( __FILE__ ))). '/yeqztsys1.0/utilityfunction/SqlHelp.class.php';<br />include_once dirname(dirname (dirname ( __FILE__ ))). '/yeqztsys1.0/Comm.class.php';<br /><br />$SqlHelper = new SqlHelp ( 'read', 'qztoa' );<br />$sql = "select * from qzt_image";<br />$query = $SqlHelper->query($sql );<br />$query_num = $SqlHelper->num_rows ($query );<br /><br />$rows = array ();  <br />$retarr = array (); <br />$query =$SqlHelper->query ( $sql );<br />if($query)<br />{<br />$arr_teainfo2 = array ();<br />while ( $arr_teainfo = $SqlHelper->fetch_assoc($query) ) {<br />$arr_teainfo2 [] = $arr_teainfo;<br />$Id=$arr_teainfo["Id"];<br />echo $arr_teainfo["Id"];<br />echo "<IMG SRC=\"Second.php3?Id=$Id\">"; <br /><br />}<br />}<br /><br /><br /><br />?>  <br />


Second.php3
<?php  <br />include_once dirname(dirname (dirname ( __FILE__ ))). '/yeqztsys1.0/utilityfunction/SqlHelp.class.php';<br />include_once dirname(dirname (dirname ( __FILE__ ))). '/yeqztsys1.0/Comm.class.php';<br /><br />$SqlHelper = new SqlHelp ( 'read', 'qztoa' );<br />$sql = "select * from qzt_image where Id=10";<br />$query = $SqlHelper->query($sql );<br />$query_num = $SqlHelper->num_rows ($query );<br /><br />$rows = array ();  <br />$retarr = array (); <br />$query =$SqlHelper->query ( $sql );<br />if($query)<br />{<br />$arr_teainfo2 = array ();<br />while ( $arr_teainfo = $SqlHelper->fetch_assoc($query) ) {<br />$arr_teainfo2 [] = $arr_teainfo;<br />$Id=$arr_teainfo["Id"];<br />$imagetype=$arr_teainfo["imagetype"];<br />//echo $arr_teainfo["images"];<br />//Header( "Content-type: $imagetype"); <br />header('Content-type: $imagetype');<br />echo $arr_teainfo["images"];<br /><br />}<br />}<br /><br />?>   <br />


请问我哪里有问题?PHP新人,不知道哪里错了

PHP
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