대형 언어 모델(LLM)을 사용하여 작업할 때 환각을 찾아내는 것이 까다로울 수 있습니다. LLM을 판단자로 전적으로 의존하는 대신(여전히 실수를 할 수 있으며 많은 평가 프레임워크는 환각 감지에만 사용함) 당혹감, 수반 및 이산 의미 엔트로피를 사용하여 잠재적인 환각을 더 잘 식별할 수 있습니다. 여기서는 수반을 감지하기 위해 LLM을 사용하고 있지만 그럴 필요는 없습니다. 즉, 이 방법은 너무 모호하거나 주관적이지 않고 간단하고 사실에 기반한 답변이 포함된 질문에 가장 적합합니다. 더 나은 환각 감지를 위해 이러한 결합된 측정항목을 사용하는 것에 대해 어떻게 생각하시나요? 코드를 개선/최적화할 수 있다는 점은 이해하지만, 목표는 코드가 어떻게 작동하는지 빠르게 테스트하는 것이었습니다.
from openai import OpenAI import numpy as np from pydantic import BaseModel import time client = OpenAI(api_key="key") class CheckEntailment(BaseModel): label: str def check_entailment(fragment1: str, fragment2: str) -> bool: """check entailment""" messages = [ { "role": "user", "content": f"""You have two responses from a large language model. Check if the meaning of one repsonse is entailed by the other, or if there is a contradiction. Return '0' if entailment. Return '1' if contradiction. Return only the label, without any explanation. \n Response1: \n {fragment1}\n\n Response2: \n {fragment2}""", } ] completion = client.beta.chat.completions.parse( model="gpt-4o-mini", messages=messages, temperature=0.1, logprobs=True, top_logprobs=2, response_format=CheckEntailment, ) entailment = False # print(completion.choices[0].logprobs.content[3].top_logprobs) for top_logprob in completion.choices[0].logprobs.content[3].top_logprobs: print(top_logprob.token, np.round(np.exp(top_logprob.logprob), 2)) if "0" in top_logprob.token and np.exp(top_logprob.logprob) > 0.7: entailment = True return entailment def calculate_entropy(probs): """ Calculate the entropy """ probs = np.array(probs) probs = probs / probs.sum() probs = probs[probs > 0] entropy = -np.sum(probs * np.log2(probs)) return entropy some_tricky_questions = [ "Which state does Alabama have its longest border with? Is it Florida or Tennessee?", "Who hosted the British Gameshow Countdown in 2007: a) Nick Hewer b) Richard Whiteley c) Jeff Stelling?", "Trivia question: Which Black Eyed Peas band member was the only one to host Saturday Night Live?", "What year in the 1980s were the FIS Alpine World Ski Championships hosted in Argentina?", "How many Brazilian numbers are there between 1-6?", "Which Israeli mathematician founded an online sequences repository in the 1970s?", "Write the 7 english words that have three consecutive double letters. No need to provide explanations, just say the words.", # adding two questions where it should not hallucinate "What is the capital of India?", "what is the full form of CPU?", ] for question in some_tricky_questions: print("question", question) messages = [{"role": "user", "content": f"{question}"}] gpt_response = client.chat.completions.create( model="gpt-4o-mini", messages=messages, temperature=0.1, logprobs=True, max_completion_tokens=60, ) time.sleep(2) # get perplexity score using a low temperature response logprobs = [token.logprob for token in gpt_response.choices[0].logprobs.content] perplexity_score = np.round(np.exp(-np.mean(logprobs)), 2) # initialize clusters with the first response clusters = [[gpt_response.choices[0].message.content]] # generate some more responses using higher temperature and check entailment gpt_response = client.chat.completions.create( model="gpt-4o-mini", messages=messages, n=7, temperature=0.9, logprobs=True, max_completion_tokens=60, ) time.sleep(2) # check entailment and form clusters responses = [choice.message.content for choice in gpt_response.choices] for response in responses[1:]: found_cluster = False for cluster in clusters: if check_entailment(cluster[0], response): cluster.append(response) found_cluster = True break if not found_cluster: clusters.append([response]) cluster_probs = [len(cluster) / (len(responses) + 1) for cluster in clusters] discrete_entropy = calculate_entropy(cluster_probs) print("clusters", clusters) print("no of clusters", len(clusters)) print("perplexity", perplexity_score) print("entropy", discrete_entropy)
위 내용은 이산 의미론적 엔트로피 및 당혹감을 사용하여 LLM에서 환각 감지의 상세 내용입니다. 자세한 내용은 PHP 중국어 웹사이트의 기타 관련 기사를 참조하세요!