>데이터 베이스 >MySQL 튜토리얼 >获取MSSQL数据字典的SQL语句

获取MSSQL数据字典的SQL语句

WBOY
WBOY원래의
2016-06-07 17:57:461149검색

获取MSSQL数据字典的实现方法。

代码如下:
CREATE VIEW dbo.vw_db_dictionary
AS
SELECT TOP 100 PERCENT dbo.sysobjects.name AS table_name,
dbo.sysproperties.[value] AS table_desc, dbo.syscolumns.name AS field,
properties.[value] AS field_desc, dbo.systypes.name AS field_type,
dbo.syscolumns.length AS field_size,
ISNULL(COLUMNPROPERTY(dbo.syscolumns.id, dbo.syscolumns.name, 'Scale'), 0)
AS field_precision, dbo.syscolumns.isnullable AS nullable,
CASE WHEN syscomments.text IS NULL
THEN '' ELSE syscomments.text END AS default_value,
CASE WHEN COLUMNPROPERTY(syscolumns.id, syscolumns.name, 'IsIdentity')
= 1 THEN '√' ELSE '' END AS is_identity, CASE WHEN EXISTS
(SELECT 1
FROM sysobjects
WHERE xtype = 'PK' AND name IN
(SELECT name
FROM sysindexes
WHERE indid IN
(SELECT indid
FROM sysindexkeys
WHERE id = syscolumns.id AND colid = syscolumns.colid)))
THEN '√' ELSE '' END AS is_key
FROM dbo.syscolumns INNER JOIN
dbo.sysobjects ON dbo.sysobjects.id = dbo.syscolumns.id INNER JOIN
dbo.systypes ON dbo.syscolumns.xtype = dbo.systypes.xtype LEFT OUTER JOIN
dbo.sysproperties properties ON dbo.syscolumns.id = properties.id AND
dbo.syscolumns.colid = properties.smallid LEFT OUTER JOIN
dbo.sysproperties ON dbo.sysobjects.id = dbo.sysproperties.id AND
dbo.sysproperties.smallid = 0 LEFT OUTER JOIN
dbo.syscomments ON dbo.syscolumns.cdefault = dbo.syscomments.id
WHERE (dbo.sysobjects.xtype = 'U')
ORDER BY dbo.sysobjects.name
성명:
본 글의 내용은 네티즌들의 자발적인 기여로 작성되었으며, 저작권은 원저작자에게 있습니다. 본 사이트는 이에 상응하는 법적 책임을 지지 않습니다. 표절이나 침해가 의심되는 콘텐츠를 발견한 경우 admin@php.cn으로 문의하세요.