在gp中取消或者中断某个用户的超长时间或者SQL存在问题的会话,如果无法拥有超级用户将无法执行该类操作。 首先我们创建两个用户t1、t2,并且使用t1登录到数据库。 [gpadmin@wx60 ~]$ psql gtlionspsql (8.2.15)Type help for help. gtlions=# select version
在gp中取消或者中断某个用户的超长时间或者SQL存在问题的会话,如果无法拥有超级用户将无法执行该类操作。首先我们创建两个用户t1、t2,并且使用t1登录到数据库。
[gpadmin@wx60 ~]$ psql gtlions psql (8.2.15) Type "help" for help. gtlions=# select version(); version ------------------------------------------------------------------------------------------------------------------------------------------------------ PostgreSQL 8.2.15 (Greenplum Database 4.2.7.2 build 1) on x86_64-unknown-linux-gnu, compiled by GCC gcc (GCC) 4.4.2 compiled on Feb 25 2014 18:05:04 (1 row) gtlions=# \du List of roles Role name | Attributes | Member of -----------+-----------------------------------+----------- gpadmin | Superuser, Create role, Create DB | gtlions=# \dn List of schemas Name | Owner --------------------+--------- gp_toolkit | gpadmin information_schema | gpadmin pg_aoseg | gpadmin pg_bitmapindex | gpadmin pg_catalog | gpadmin pg_toast | gpadmin public | gpadmin (7 rows) gtlions=# create user t1 ; NOTICE: resource queue required -- using default resource queue "pg_default" CREATE ROLE gtlions=# create user t2; NOTICE: resource queue required -- using default resource queue "pg_default" CREATE ROLE gtlions=# \c gtlions t1 You are now connected to database "gtlions" as user "t1". 接下来我们使用用户t2登录到数据库,检查当前会话并尝试取消或者中断用户t1的会话。
[gpadmin@wx60 ~]$ psql -U t2 gtlions psql (8.2.15) Type "help" for help. gtlions=> select * from pg_stat_activity ; datid | datname | procpid | sess_id | usesysid | usename | current_query | waiting | query_start | backend_start | client_addr | client_port | application_name | xact_start -------+---------+---------+---------+----------+---------+----------------------------------+---------+-------------------------------+------------------------------- +-------------+-------------+------------------+------------------------------- 16992 | gtlions | 3395 | 13 | 25881 | t2 | select * from pg_stat_activity ; | f | 2014-10-11 09:25:56.197394+08 | 2014-10-11 09:25:43.293684+08 | | -1 | psql | 2014-10-11 09:25:56.197394+08 16992 | gtlions | 3384 | 12 | 25880 | t1 | <insufficient privilege> | | | | | | psql | (2 rows) gtlions=> select pg_cancel_backend(3384); ERROR: must be superuser to signal other server processes gtlions=> 会发现非超级用户无法执行取消或者中断其他用户的会话操作。 解决办法是自定义一个函数,并授权给t2用户执行权限,这样就可以实现上述操作了。
create or replace function session_mgr(procpid integer, opertype character) returns boolean as $BODY$ declare ret boolean; begin if opertype = 'c' then ret := (select pg_catalog.pg_cancel_backend(procpid)); elsif opertype = 'k' then ret := (select pg_catalog.pg_terminate_backend(procpid)); end if; return ret; end; $BODY$ LANGUAGE plpgsql security definer; gtlions=# grant execute on function session_mgr(integer, character) to t2; GRANT gtlions=# \c gtlions t1 You are now connected to database "gtlions" as user "t1". gtlions=> 接着使用用户t2进行相关操作。
[gpadmin@wx60 ~]$ psql -U t2 gtlions psql (8.2.15) Type "help" for help. gtlions=> select * from pg_stat_activity ; datid | datname | procpid | sess_id | usesysid | usename | current_query | waiting | query_start | backend_start | client_addr | client_port | application_name | xact_start -------+---------+---------+---------+----------+---------+----------------------------------+---------+-------------------------------+------------------------------- +-------------+-------------+----------------------------+------------------------------- 16992 | gtlions | 4034 | 19 | 25881 | t2 | select * from pg_stat_activity ; | f | 2014-10-11 09:48:53.767859+08 | 2014-10-11 09:48:51.285594+08 | | -1 | psql | 2014-10-11 09:48:53.767859+08 16992 | gtlions | 3678 | 15 | 10 | gpadmin | <insufficient privilege> | | | | | | pgAdmin III - ????????? | 16992 | gtlions | 3704 | 16 | 10 | gpadmin | <insufficient privilege> | | | | | | pgAdmin III - ???????????? | 16992 | gtlions | 4023 | 18 | 25880 | t1 | <insufficient privilege> | | | | | | psql | (4 rows) gtlions=> select session_mgr(4023,'c'); session_mgr ------------- t (1 row) gtlions=> select * from pg_stat_activity ; datid | datname | procpid | sess_id | usesysid | usename | current_query | waiting | query_start | backend_start | client_addr | client_port | application_name | xact_start -------+---------+---------+---------+----------+---------+----------------------------------+---------+-------------------------------+------------------------------- +-------------+-------------+----------------------------+------------------------------- 16992 | gtlions | 4034 | 19 | 25881 | t2 | select * from pg_stat_activity ; | f | 2014-10-11 09:52:03.279186+08 | 2014-10-11 09:48:51.285594+08 | | -1 | psql | 2014-10-11 09:52:03.279186+08 16992 | gtlions | 4065 | 20 | 10 | gpadmin | <insufficient privilege> | | | | | | pgAdmin III - ???????????? | 16992 | gtlions | 3678 | 15 | 10 | gpadmin | <insufficient privilege> | | | | | | pgAdmin III - ????????? | 16992 | gtlions | 3704 | 16 | 10 | gpadmin | <insufficient privilege> | | | | | | pgAdmin III - ???????????? | 16992 | gtlions | 4023 | 18 | 25880 | t1 | <insufficient privilege> | | | | | | psql | (5 rows) gtlions=> select session_mgr(4023,'k'); session_mgr ------------- t (1 row) gtlions=> select * from pg_stat_activity ; datid | datname | procpid | sess_id | usesysid | usename | current_query | waiting | query_start | backend_start | client_addr | client_port | application_name | xact_start -------+---------+---------+---------+----------+---------+----------------------------------+---------+-------------------------------+------------------------------- +-------------+-------------+----------------------------+------------------------------- 16992 | gtlions | 4034 | 19 | 25881 | t2 | select * from pg_stat_activity ; | f | 2014-10-11 09:52:28.473137+08 | 2014-10-11 09:48:51.285594+08 | | -1 | psql | 2014-10-11 09:52:28.473137+08 16992 | gtlions | 4065 | 20 | 10 | gpadmin | <insufficient privilege> | | | | | | pgAdmin III - ???????????? | 16992 | gtlions | 3678 | 15 | 10 | gpadmin | <insufficient privilege> | | | | | | pgAdmin III - ????????? | 16992 | gtlions | 3704 | 16 | 10 | gpadmin | <insufficient privilege> | | | | | | pgAdmin III - ???????????? | 16992 | gtlions | 4189 | 21 | 25880 | t1 | <insufficient privilege> | | | | | | psql | (5 rows) gtlions=> 最后检查下t1当前进程。
gtlions=> select version(); FATAL: terminating connection due to administrator command server closed the connection unexpectedly This probably means the server terminated abnormally before or while processing the request. The connection to the server was lost. Attempting reset: Succeeded. -EOF-

mysqlblobshavelimits : tinyblob (255bodes), blob (65,535 bytes), mediumblob (16,777,215 bctes), andlongblob (4,294,967,295 Bytes) .tousebl obseffectical : 1) 고려 사항을 고려합니다

MySQL에서 사용자 생성을 자동화하기위한 최고의 도구 및 기술은 다음과 같습니다. 1. MySQLworkBench, 중소형 환경에 적합하고 사용하기 쉽지만 자원 소비가 높습니다. 2. 다중 서버 환경에 적합한 Ansible, 간단하지만 가파른 학습 곡선; 3. 사용자 정의 파이썬 스크립트, 유연하지만 스크립트 보안을 보장해야합니다. 4. 꼭두각시와 요리사는 대규모 환경에 적합하며 복잡하지만 확장 가능합니다. 선택할 때 척도, 학습 곡선 및 통합 요구를 고려해야합니다.

예, youcansearchinsideablobinmysqlusingspecifictechniques.1) converttheblobtoautf-8stringwithConvertFunctionandSearchusing

mysqloffersvariousStringDatatatypes : 1) charfixed-lengthstrings, 이상적인 원인이 길이의 길이가 길이 스트링스, 적합한 포르 플리드 슬리 키나 이름; 3) TextTypesforlargerText, goodforblogpostsbutcactperformance;

TomasterMySQLBLOBs,followthesesteps:1)ChoosetheappropriateBLOBtype(TINYBLOB,BLOB,MEDIUMBLOB,LONGBLOB)basedondatasize.2)InsertdatausingLOAD_FILEforefficiency.3)Storefilereferencesinsteadoffilestoimproveperformance.4)UseDUMPFILEtoretrieveandsaveBLOBsco

blobdatatypesinmysqlareusedforvoringlargebinarydatalikeimagesoraudio.1) useblobtypes (tinyblobtolongblob) 기반 론다 타지 세인. 2) StoreBlobsin perplate petooptimize 성능.

toadduserstomysqlfromthecommandline, loginasroot, whenUseCreateUser'Username '@'host'IdentifiedBy'Password '; toCreateAwUser.grantPerMissionswithGrantAllilegesOndatabase

mysqlofferSeightStringDatatatypes : char, varchar, binary, varbinary, blob, text, enum and set.1) charisfix-length, 2) varcharisvariable-length, 효율적 인 datalikenames.3) binaryandvarbinary-binary Binary Binary Binary Binary Binary Binary Binary-Binary


핫 AI 도구

Undresser.AI Undress
사실적인 누드 사진을 만들기 위한 AI 기반 앱

AI Clothes Remover
사진에서 옷을 제거하는 온라인 AI 도구입니다.

Undress AI Tool
무료로 이미지를 벗다

Clothoff.io
AI 옷 제거제

Video Face Swap
완전히 무료인 AI 얼굴 교환 도구를 사용하여 모든 비디오의 얼굴을 쉽게 바꾸세요!

인기 기사

뜨거운 도구

ZendStudio 13.5.1 맥
강력한 PHP 통합 개발 환경

SublimeText3 Mac 버전
신 수준의 코드 편집 소프트웨어(SublimeText3)

Dreamweaver Mac版
시각적 웹 개발 도구

드림위버 CS6
시각적 웹 개발 도구

안전한 시험 브라우저
안전한 시험 브라우저는 온라인 시험을 안전하게 치르기 위한 보안 브라우저 환경입니다. 이 소프트웨어는 모든 컴퓨터를 안전한 워크스테이션으로 바꿔줍니다. 이는 모든 유틸리티에 대한 액세스를 제어하고 학생들이 승인되지 않은 리소스를 사용하는 것을 방지합니다.