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ログイン ページで [ログイン] をクリックした後、データをクエリできず、ログインも成功しませんが、データベースのクエリ操作は成功します。理由は何ですか?

<?php

session_start();

error_reporting(E_ERROR);

$zh=$_POST['zh'];

$password=$_POST['パスワード'];

$user=$_POST['ユーザー'] ;

if(!isset($user)){

echo "<script>alert('请选择用户类型');</script>";

echo "<script>history.go(-1);</script>";

}

$conn=mysqli_connect("localhost","8admin"," 8admin")or die('连接データベース库失败');

$db=mysqli_select_db($conn,"8_com");

$sql1="SELECT*FROM admin WHERE admin_id =' $zh' AND パスワード='$password' ";

$sql2="* 教師から選択 ここで、teach_id ='$zh' およびパスワード='$password' ";

$sql3 ="select * from students where stuno ='$zh' およびpassword='$password' ";

mysqli_query($conn,"set names utf8");

switch($user ){

case 1:$result=mysqli_query($conn,$sql)or die('查询不到');

$row = mysqli_fetch_array($conn,$result);

$count=$row[0];

if($count!=""){

$url="index_admin.php";

$_SESSION['admin_name']=$row['name'];

$_SESSION['admin_id']= $row['admin_id'];

echo "<script type='text/javascript'>"."location.href='".$url."'"."</script> ;";

}

else {

echo "<script>alert('账户または密码错误');</script>";

echo "<script>history.go(-1);</script>";

}

Break;

case 2:$result =mysqli_query($sql2,$conn);

$result=mysqli_query($sql2,$conn)or die('查询不到');

$row = mysqli_fetch_array($result);

$count=$row[0];

if($count!=""){

$url="index_Teacher.php";

$_SESSION['Teacher_name']=$row['name'];

$_SESSION['Teacher_id']=$row['teach_id'];

echo "<script type='text/javascript'>"."location.href=' ".$url."'"."</script>";

}

else {

echo "