変数の受け渡しのための Ajax および PHP 実装コード

$.ajax({
url: 'query.php',
data: {id:10},
datatype: json
success: function(results) {
if (results.msg == 'success) ') {
for (var i in data) {
$('#content').append(
'id = ' + results.data[i].id + ', description = ' + results.data[i] .description + ', msrp = ' + results.data[i].msrp
);
}
} else {
$('#content').append(results.msg);
}
}
});

php代：

if (isset($_GET['id'])) {
$sql = "SELECT id、説明、msrp FROM tbl WHERE id = '{$_GET['id'] }'";
$return = array();
if ($result = mysql_query($sql)) {
if (mysql_num_rows($result)) {
$return['msg'] = 'success';
while ($row = mysql_fetch_assoc($result)) {
$return['data'][] = $row;
}
} else {
$return['msg'] = '結果が見つかりません';
} else {
$return['msg'] = 'クエリが失敗しました';
}
header("Content-type: application/json");
echo json_encode($result);
}