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特定の項目の配列合計問題
- WBOYオリジナル
- 2016-06-23 14:20:281019ブラウズ
配列 a が与えられた場合:
array ( 0 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5A', 'mount_total' => '1', 'total' => '16', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121015001', ), 1 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5B', 'mount_total' => '2', 'total' => '32', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121015002', ), 2 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5B', 'mount_total' => '2', 'total' => '32', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121226001', ),)
配列内の項目 cust_no に対応する packageno の結果と、stock_no に対応する mount_total 項目と total 項目の合計の結果を取得するにはどうすればよいですか?
cust_no が 310F61VA5A であると仮定すると、対応するパッケージ番号は CVT121225001 です。
cust_no が 310F61VA5B の場合、対応するパッケージ番号は CVT121225002、CVT121226001 です。
stock_noがSU13080800340の場合、取得されるmount_total結果は3(1+2)、合計結果は48(16+32)となります。
この効果を実現するにはどうすればよいですか?
ディスカッションへの返信 (解決策)
$a = array ( 0 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5A', 'mount_total' => '1', 'total' => '16', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121015001', ), 1 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5B', 'mount_total' => '2', 'total' => '32', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121015002', ), 2 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5B', 'mount_total' => '2', 'total' => '32', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121226001', ), );function foo1($cust_no,$a=array()){ foreach($a as $each){ if($each['cust_no'] == $cust_no){ $res[] = $each['packageno']; } } if($res){ return implode(",",$res); }else{ return false; }}function foo2($stock_no,$a=array()){ foreach($a as $each){ if($each['stock_no'] == $stock_no){ $mount_total[] = $each['mount_total']; $total[] = $each['total']; } } $mount_total = array_unique($mount_total); //去重复 $total = array_unique($total); $res['mount_total'] = array_sum($mount_total); $res['total'] = array_sum($total); return $res;}var_export(foo1("310F61VA5B",$a));var_export(foo2("SU13080800340",$a)); 'CVT121015002,CVT121226001'
array ( 'mount_total' => 3, 'total' => 48, )
$ar=array ( 0 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5A', 'mount_total' => '1', 'total' => '16', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121015001', ), 1 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5B', 'mount_total' => '2', 'total' => '32', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121015002', ), 2 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5B', 'mount_total' => '2', 'total' => '32', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121226001', ),);foreach($ar as $v){ $a[$v['cust_no']][]=$v['packageno']; $b[$v['stock_no']][]=$v['mount_total']; $c[$v['stock_no']][]=$v['total'];}print_r($a);print_r($b);print_r($c); 配列
(
] [310f61va5a] =＆gt;指定された値を持つ配列要素の packageno 値が必要な結果になります。
2 番目の質問は、配列要素の各 Stock_no フィールドの値を決定し、指定された値を持つ配列要素の 2 つの必須フィールドを格納します。値を配列に入力し、ループが終了したら重複を削除して加算します
$a = array ( 0 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5A', 'mount_total' => '1', 'total' => '16', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121015001', ), 1 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5B', 'mount_total' => '2', 'total' => '32', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121015002', ), 2 => array ( 'stock_no' => 'SU13080800340', 'adress' => 'B', 'arr_time' => '2013-08-14 09:00:00', 'c_type' => 'P32E', 'cust_no' => '310F61VA5B', 'mount_total' => '2', 'total' => '32', 'c1_time' => '2013-08-10 15:00:00', 'packageno' => 'CVT121226001', ),);$res = array();foreach($a as $item) { if(! isset($res[$item['stock_no']][$item['cust_no']])) { $res[$item['stock_no']][$item['cust_no']] = $item; }else { $res[$item['stock_no']][$item['cust_no']]['mount_total'] += $item['mount_total']; $res[$item['stock_no']][$item['cust_no']]['total'] += $item['total']; $res[$item['stock_no']][$item['cust_no']]['packageno'] .= ',' .$item['packageno']; }}foreach($res as &$item) $item = array_values($item);print_r($res);Array (
[SU13080800340] => Array
(
[0] => Array
(
[stock_no] => SU13080800340
[adress] => B
[arr_time] => 2013-08-14 09:00:00
[c_type] => P32E
[cust_no] => 310F61VA5A
[mount_total] => 1
[total] => 16
[c1_time] => 2013-08-10 15:00:00
[packageno] => CVT121015001
)
[1] => Array
(
[stock_no] => SU13080800340
[adress] => B
[arr_time] => 2013-08-14 09:00:00
[c_type] => P32E
[cust_no] => 310F61VA5B
[mount_total] => 4
[total] => 64
[c1_time] => 2013-08-10 15:00:00
[packageno] => CVT121015002,CVT121226001
)
)
)
[code=php]
Array
(
[310F61VA5A] => Array
(
[0] => CVT121015001
)
[310F61VA5B] => Array
(
[0] => CVT121015002
[1] => CVT121226001
)
)
Array
(
[SU13080800340] => Array
(
[0] => 1
[1] => 2
[2] => 2
)
)
Array
(
[SU13080800340] => Array
(
[0] => 16
[1] => 32
[2] => 32
)
)
第一项OK，但是mount_total和total的求和结果不对，我要的是stock_no为SU13080800340时，求得的mount_total结果为3（1+2），total结果为48（16+32）。
$res = array();foreach($a as $item) { if(! isset($res[$item['stock_no']][$item['cust_no']])) { $res[$item['stock_no']][$item['cust_no']] = $item; }else { $res[$item['stock_no']][$item['cust_no']]['mount_total'] += $item['mount_total']; $res[$item['stock_no']][$item['cust_no']]['total'] += $item['total']; $res[$item['stock_no']][$item['cust_no']]['packageno'] .= ',' .$item['packageno']; }}foreach($res as &$item) $item = array_values($item);print_r($res); 我想要得到的stockno的求和结果是mount_total为3（2+1），total结果为48（16+32）。
楼主这种问题 应该算是比较基础的 我有点好奇为什么会纠结于
Array
(
[0] => 16
[1] => 32
[2] => 32
)
这种数组的加和? 你的需求应该是去了重复求和.... 一个PHP函数的事情...
你的数组中三个stock_no的值不是一样的吗，都为 SU13080800340 吧，难道我眼花了？
那是你的数据给错了
'cust_no' => '310F61VA5A',
'mount_total' => '1',
'total' => '16',
'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',
'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',
那是你的数据给错了
'cust_no' => '310F61VA5A',
'mount_total' => '1',
'total' => '16',
'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',
'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',
那我再想想。
你的数组中三个stock_no的值不是一样的吗，都为 SU13080800340 吧，难道我眼花了？
那怎么去重复求和呢？
データが間違っているためです
'cust_no' => '310F61VA5A',
'mount_total' => '16',
= > '310F61VA5B',
'mount_total' => '2'、
'total' => '310F61VA5B'、
'mount_total' = > 'total' => '32'、
合計を繰り返したい場合はどうすればよいでしょうか?
それはあなたのデータが間違っているからです
'cust_no' => '310F61VA5A',
'mount_total' => '16',
'mount_total' => '2'、
'total' => '310F61VA5B'、
'mount_total' =>
'total' => '32',
合計を繰り返したい場合はどうすればよいでしょうか?
和を繰り返して1階を見上げると....