直奔主题,如下SQL语句(via:女孩礼物网): SELECT COUNT(* ) AS COUNT,REQUEST,METHOD FROM REQUESTMETH GROUP BY REQUEST,METHOD HAVING (REQUEST = ' FC.OCEAN.JOB.SERVER.CBIZOZBKHEADER ' OR REQUEST= ' FC.Ocean.Job.Server.CBizOzDocHeader ' )AND COU
直奔主题,如下SQL语句(via:女孩礼物网):
SELECT COUNT(*<span>) AS COUNT,REQUEST,METHOD FROM REQUESTMETH GROUP BY REQUEST,METHOD HAVING (REQUEST </span>=<span>'</span><span>FC.OCEAN.JOB.SERVER.CBIZOZBKHEADER</span><span>'</span> OR REQUEST=<span>'</span><span>FC.Ocean.Job.Server.CBizOzDocHeader</span><span>'</span><span>) AND COUNT(</span>*) ><span>3</span><span> ORDER BY REQUEST</span>
注意事项:
HAVING后的条件不能用别名COUNT>3 必须使用COUNT(*) >3,否则报:列名 'COUNT' 无效。
having 子句中的每一个元素并不一定要出现在select列表中
如果把该语句写成:
SELECT COUNT(*<span>) AS COUNT,REQUEST,METHOD FROM REQUESTMETH GROUP BY REQUEST ORDER BY REQUEST</span>
那么将报:
选择列表中的列 'REQUESTMETH.method' 无效,因为该列没有包含在聚合函数或 GROUP BY 子句中。
注意:
1、使用GROUP BY 子句时,SELECT 列表中的非汇总列必须为GROUP BY 列表中的项。
2、分组时,所有的NULL值分为一组。
3、GROUP BY 列表中一般不允许出现复杂的表达试、显示标题以及SELECT列表中的位置标号。
如:
SELECT REQUEST,METHOD, COUNT(*<span>) AS COUNT FROM REQUESTMETH GROUP BY REQUEST,</span><span>2</span> ORDER BY REQUEST
错误信息为:每个 GROUP BY 表达式都必须包含至少一个列引用。
GROUP BY 中使用 ORDER BY注意事项:
SELECT COUNT(*) AS COUNT FROM REQUESTMETH GROUP BY REQUEST,METHOD ORDER BY REQUEST,METHOD
--这样是允许的, ORDER BY后面的字段包含在GROUP BY 子句中
SELECT COUNT(*) AS COUNTS FROM REQUESTMETH GROUP BY REQUEST ORDER BY COUNT(*) DESC
--这样是允许的,ORDER BY后面的字段包含在聚合函数中,结果集同下面语句一样
SELECT COUNT(*) AS COUNTS FROM REQUESTMETH GROUP BY REQUEST ORDER BY COUNTS DESC
--这样是允许的,区别于HAVING,HAVING后不允许跟聚集函数的别名作为过滤条件
SELECT COUNT(*) AS COUNTS FROM REQUESTMETH GROUP BY REQUEST ORDER BY METHOD
--这样是错误的:ORDER BY 子句中的列 "REQUESTMETH.method" 无效,因为该列没有包含在聚合函数或 GROUP BY 子句中。
SELECT DISTINCT 中使用 ORDER BY注意事项:
SELECT DISTINCT BOOKID FROM BOOK ORDER BY BOOKNAME
以上语句将报:
--如果指定了SELECT DISTINCT,那么ORDER BY 子句中的项就必须出现在选择列表中。
因为以上语句类似
SELECT BOOKID FROM BOOK GROUP BY BOOKID ORDER BY BOOKNAME
其实错误信息也为:
--ORDER BY子句中的列"BOOK.BookName" 无效,因为该列没有包含在聚合函数或GROUP BY 子句中。
应该改为:
SELECT DISTINCT BOOKID,BOOKNAME FROM BOOK ORDER BY BOOKNAME
<span>SELECT DISTINCT BOOKID,BOOKNAME FROM BOOK<br></span>
SELECT BOOKID,BOOKNAME FROM BOOK GROUP BY BOOKID,BOOKNAME
以上两句查询结果是一致的,DISTINCT的语句其实完全可以等效的转换为GROUP BY语句