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How to remove the seperator line in footerLayout
? I have a footerLayout
below the listView
, used to display the totalAmount as shown below. If I click the seperator line in footerLayout
, my app crashed.
My MainActivity
AllAdapter obj = new AllAdapter(getApplication(), search, listview,imageView,text,button);
footerLayout = (LinearLayout) getLayoutInflater().inflate(R.layout.under_listview, null);
totalAmount = (TextView) footerLayout.findViewById(R.id.amount);
LogCat error
java.lang.IndexOutOfBoundsException: Invalid index 2, size is 2
at java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:251)
at java.util.ArrayList.get(ArrayList.java:304)
at com.example.tony.monthlyexpenses.adapter.AllAdapter.getItem(AllAdapter.java:61)
at com.example.tony.monthlyexpenses.QuickExpenses$1.onItemClick(QuickExpenses.java:88)
at android.widget.AdapterView.performItemClick(AdapterView.java:301)
The error pointed to listView
onClickListener
listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
mClickedPosition = position;
Expenses o = (Expenses) obj.getItem(position);
String day = o.getDate();
}
});
AllAdapter
public Expenses getItem(int position) {
return search.get(position);
}
The footerLayout is supposed to be displayed outside the listView, not inside. How can I get rid of this ?
I also have activity_main.xml
, AllAdapter
class, all_adapter.xml
for ListView
and also under_listview.xml
for the footerLayout
.
activity_main
AllAdapter
under_listview
How to move the footerLayout out from the ListView ?
I add android:footerpidersEnabled="false"
now become like this
But still clickable !!!
谁知道问题出在哪?
footerLayout
被按时如何不出现灰色?
ringa_lee2017-04-17 18:03:43
很简单,但也很容易出错的问题,加了footer
后,你的listview item
数量是3
,但adapter
的viewcount
其实并没有变成3
,所以在你点击footer时执行的是obj.getItem(2)
,肯定是数组越界异常了。对于添加了header或footer的listview
,正确的取item方法应该是
listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
Expenses o = (Expenses) listView.getAdapter().getItem(position);
if(o != null){
mClickedPosition = position;
//Expenses o = (Expenses) obj.getItem(position);
String day = o.getDate();
}
}
});
header或footer属于AdapterView的子view
,listView.getAdapter().getItem(position);
能确保你取2的position时不越界,再做对象空判断。
天蓬老师2017-04-17 18:03:43
你不能使用setOnItemClickListener 来作为footview的点击事件,我认为你应该单独的去设置
例如 footview.setonClickListener(new OnClickListener{}); 祝你好运
伊谢尔伦2017-04-17 18:03:43
你这个是数组下标越界了啊,你的数组size是2,所以对应的下标只能是0和1,但是你在使用的时候用了2,错误显示你有个无效的index 2,你自己找下第61行和第88行,看是否有地方调用了index是2的
伊谢尔伦2017-04-17 18:03:43
将footerLayout
移出listView
的写法是
listview.addFooterView(footerLayout, null, false);