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Comment puis-je écrire la fonction qui renvoie success : success dans ses paramètres ?
function success(data){
console.log(data);
}
jsonp({
url:'https://sp0.baidu.com/5a1Fazu8AA54nxGko9WTAnF6hhy/su',
type:'get',
data:{
wd:'jsonp'
},
callback :'cb',
success:success
});
function jsonp(options){
var url = options.url;
var data = options.data;
format(data,options,function(str,callback){
var oBody = document.getElementsByTagName('body')[0];
var oScript = document.createElement('script');
oScript.setAttribute('src',url+'?'+str + options.callback+'='+callback);
oBody.appendChild(oScript);
});
return options.success;
};
function format(data,options,callback){
var callbackName = '';
var str = '';
for(var p in data){//格式化get提交的参数
str += p+'='+data[p]+'&';
}
for(var p in options){
if(options[p] == options.success){//取出要返回的函数名
callbackName = p;
callback && callback(str,callbackName);
}
}
}
如果是这么写success:function(data){conosle.log(data);}
会报一个success is undefined错误
ringa_lee2017-07-05 11:08:09
https://jsfiddle.net/hsfzxjy/...
jsonp({
url: 'https://sp0.baidu.com/5a1Fazu8AA54nxGko9WTAnF6hhy/su',
type: 'get',
data:{
wd: 'jsonp'
},
callback: 'cb',
success: function (data) { console.log(data) }
});
function jsonp (options) {
let url = options.url
let data = options.data
let oBody = document.getElementsByTagName('body')[0]
let oScript = document.createElement('script')
let callbackName = 'cb' + (~~(Math.random()*0xffffff)).toString(16)
window[callbackName] = function (result) {
options.success(result)
}
data[options.callback] = callbackName
oScript
.setAttribute('src', url + '?' + format(data))
oBody.append(oScript)
}
function format(data) {
let str = ''
for (var p in data) {
str += encodeURIComponent(p) + '=' + encodeURIComponent(data[p]) + '&'
}
return str
}