Maison > Article > développement back-end > php print_r 还原成数组的代码原理?
<code>class Trie { protected $dict = array(); protected $buf = ''; function set($word, $value='') { if(is_array($word)) foreach($word as $k=>$v) $this->set($k, $v); $p =& $this->dict; foreach(str_split($word) as $ch) { if(! isset($p[$ch])) $p[$ch] = array(); $p =& $p[$ch]; } $p['val'] = $value; return $this; } function parse($str) { $this->doc = $str; $this->len = strlen($str); $i = 0; while($i len) { $t = $this->find($this->dict, $i); if($t) { $i = $t; $this->buf = ''; }else $this->buf .= $this->doc{$i++}; } } protected function find(&$p, $i) { if($i >= $this->len) return $i; $t = 0; $n = $this->doc{$i}; if( isset($p[$n]) ) $t = $this->find($p[$n], $i+1); if($t) return $t; if( isset($p['val']) ) { $ar = explode(',', $p['val']); call_user_func_array( array($this, array_shift($ar)), $ar ); return $i; } return $t; } function __call($method, $param) { echo "****\n$this->buf 未定义方法:$method 参数:" . join(',', $param) . "<br>\n"; } } class App extends Trie { public $res = array(); protected $stack = array(); protected $keyname = ''; protected $buf = ''; function __construct() { $this->stack[] =& $this->res; } protected function group() { if(! $this->keyname) return; $cnt = count($this->stack) - 1; $this->stack[$cnt][$this->keyname] = array(); $this->stack[] =& $this->stack[$cnt][$this->keyname]; $this->keyname = ''; } protected function brackets($c) { $cnt = count($this->stack) - 1; switch($c) { case ')': if($this->keyname) $this->stack[$cnt][$this->keyname] = trim($this->buf); $this->keyname = ''; array_pop($this->stack); break; case '[': if($this->keyname) $this->stack[$cnt][$this->keyname] = trim($this->buf); break; case ']': $this->keyname = $this->buf; } $this->buf = ''; } }</code>
这段代码我在几个示例中看到,原始的出处不知道,它是如何实现print_r 的显示成数组呢?求注释,谢谢!
中间常用的是&,来回几个我就晕了。
<code>class Trie { protected $dict = array(); protected $buf = ''; function set($word, $value='') { if(is_array($word)) foreach($word as $k=>$v) $this->set($k, $v); $p =& $this->dict; foreach(str_split($word) as $ch) { if(! isset($p[$ch])) $p[$ch] = array(); $p =& $p[$ch]; } $p['val'] = $value; return $this; } function parse($str) { $this->doc = $str; $this->len = strlen($str); $i = 0; while($i len) { $t = $this->find($this->dict, $i); if($t) { $i = $t; $this->buf = ''; }else $this->buf .= $this->doc{$i++}; } } protected function find(&$p, $i) { if($i >= $this->len) return $i; $t = 0; $n = $this->doc{$i}; if( isset($p[$n]) ) $t = $this->find($p[$n], $i+1); if($t) return $t; if( isset($p['val']) ) { $ar = explode(',', $p['val']); call_user_func_array( array($this, array_shift($ar)), $ar ); return $i; } return $t; } function __call($method, $param) { echo "****\n$this->buf 未定义方法:$method 参数:" . join(',', $param) . "<br>\n"; } } class App extends Trie { public $res = array(); protected $stack = array(); protected $keyname = ''; protected $buf = ''; function __construct() { $this->stack[] =& $this->res; } protected function group() { if(! $this->keyname) return; $cnt = count($this->stack) - 1; $this->stack[$cnt][$this->keyname] = array(); $this->stack[] =& $this->stack[$cnt][$this->keyname]; $this->keyname = ''; } protected function brackets($c) { $cnt = count($this->stack) - 1; switch($c) { case ')': if($this->keyname) $this->stack[$cnt][$this->keyname] = trim($this->buf); $this->keyname = ''; array_pop($this->stack); break; case '[': if($this->keyname) $this->stack[$cnt][$this->keyname] = trim($this->buf); break; case ']': $this->keyname = $this->buf; } $this->buf = ''; } }</code>
这段代码我在几个示例中看到,原始的出处不知道,它是如何实现print_r 的显示成数组呢?求注释,谢谢!
中间常用的是&,来回几个我就晕了。
&
代表引用,比如
<code class="php">$a = &$b;</code>
就代表$a
和$b
是同一个引用,修改$a
也会修改$b
的值,修改$b
也影响$a
。不加上&
就代表把$b
的值复制一份给$a
,两者都是独立的。
而函数(方法)的参数列表里加上&
,就代表按引用传递了,不加就是按值传递,这是编程的基本概念,不用多说了吧。
需要注意的是对象类型,不管加不加&
都是引用。
看看这个