javascript - JS POST 到PHP。

<code><script>
var images = document.getElementsByClassName("c1");
var imageStr = "";
for(var i=0;i<images.length;i++){
   imageStr+=images[i].src+'_';
}

alert(imageStr);
</script>
</code>

如何设定一个按钮，点击后post imageStr里面的数组到PHP

<code>$imageStr = "http://127.0.0.1/down/123.gif__http://127.0.0.1/down/8095680852_893f685cbd_q.jpg__http://127.0.0.1/down/8018953043_c6ef9e3b29_q.jpg__";
</code>

提问前请先搜索相关答案:
https://segmentfault.com/sear...

回复内容：

<code><script>
var images = document.getElementsByClassName("c1");
var imageStr = "";
for(var i=0;i<images.length;i++){
   imageStr+=images[i].src+'_';
}

alert(imageStr);
</script>
</code>

如何设定一个按钮，点击后post imageStr里面的数组到PHP

<code>$imageStr = "http://127.0.0.1/down/123.gif__http://127.0.0.1/down/8095680852_893f685cbd_q.jpg__http://127.0.0.1/down/8018953043_c6ef9e3b29_q.jpg__";
</code>

提问前请先搜索相关答案:
https://segmentfault.com/sear...

例子

<code>$( "#lock_submit").click(function (){
 var lock_form = $("#lock_form").serialize(); // 参数带在form里面用form表单
 var onePush = "xxx/xxx/xxx.php" ;
 var imageStr ="http://127.0.0.1/down/123.gif__http://127.0.0.1/down/8095680852_893f685cbd_q.jpg__http://127.0.0.1/down/8018953043_c6ef9e3b29_q.jpg__";
    $.ajax({
        url: onePush ,
        type:"POST",
        data：{image:imageStr},//data:lock_form  form提交
        dataType : "json",
        success :function(data){

            if(data.status== 1){
                alert('操作成功')
                // 刷选页面
                location. reload();

            }else{
               alert('操作失败')
            }
        }
    })
})
</code>

表单提交就可以了

$.post(url,{imageStr:$imageStr},function(res){

<code>//do somethings
</code>

})