Go Sync Mutex : modes normal et famine

This is an excerpt of the post; the full post is available here: Golang Sync Mutex: Normal and Starvation Mode.

Mutex, or MUTual EXclusion, in Go is basically a way to make sure that only one goroutine is messing with a shared resource at a time. This resource can be a piece of code, an integer, a map, a struct, a channel, or pretty much anything.

Now, the explanation above isn't strictly the 'academic' definition, but it's a useful way to understand the concept.

In today's discussion, we're still going from the problem, moving on to the solution, and then diving into how it's actually put together under the hood.

Why we need sync.Mutex?

If you've spent enough time messing around with maps in Go, you might run into a nasty error like this:

fatal error: concurrent map read and map write

This happens because we're not protecting our map from multiple goroutines trying to access and write to it at the same time.

Now, we could use a map with a mutex or a sync.Map, but that's not our focus today. The star of the show here is sync.Mutex, and it's got three main operations: Lock, Unlock, and TryLock (which we won't get into right now).

When a goroutine locks a mutex, it's basically saying, 'Hey, I'm going to use this shared resource for a bit,' and every other goroutine has to wait until the mutex is unlocked. Once it's done, it should unlock the mutex so other goroutines can get their turn.

Simple as that, Let's see how it works with a simple counter example:

var counter = 0
var wg sync.WaitGroup

func incrementCounter() {
    counter++
    wg.Done()
}

func main() {
    for i := 0; i < 1000; i++ {
        wg.Add(1)
        go incrementCounter()
    }

    wg.Wait()
    fmt.Println(counter)
}

So, we've got this counter variable that's shared between 1000 goroutines. A newcomer to Go would think the result should be 1000, but it never is. This is because of something called a "race condition."

A race condition happens when multiple goroutines try to access and change shared data at the same time without proper synchronization. In this case, the increment operation (counter++) isn't atomic.

It's made up of multiple steps, below is the Go assembly code for counter++ in ARM64 architecture:

MOVD    main.counter(SB), R0
ADD $1, R0, R0
MOVD    R0, main.counter(SB)

The counter++ is a read-modify-write operation and these steps above aren't atomic, meaning they're not executed as a single, uninterruptible action.

For instance, goroutine G1 reads the value of counter, and before it writes the updated value, goroutine G2 reads the same value. Both then write their updated values back, but since they read the same original value, one increment is practically lost.

Race condition

Using the atomic package is a good way to handle this, but today let's focus on how a mutex solves this problem:

var counter = 0
var wg sync.WaitGroup
var mutex sync.Mutex

func incrementCounter() {
    mutex.Lock()
    counter++
    mutex.Unlock()
    wg.Done()
}

func main() {
    for i := 0; i < 1000; i++ {
        wg.Add(1)
        go incrementCounter()
    }

    wg.Wait()
    fmt.Println(counter)
}

Now, the result is 1000, just as we expected. Using a mutex here is super straightforward: wrap the critical section with Lock and Unlock. But watch out, if you call Unlock on an already unlocked mutex, it'll cause a fatal error sync: unlock of unlocked mutex.

It's usually a good idea to use defer mutex.Unlock() to ensure the unlock happens, even if something goes wrong. We've also got an article about Golang Defer: From Basic To Traps.

Also, you could set GOMAXPROCS to 1 by runnning runtime.GOMAXPROCS(1), and the result would still be correct at 1000. This is because our goroutines wouldn't be running in parallel, and the function is simple enough not to be preempted while running.

Mutex Structure: The Anatomy

Before we dive into how the lock and unlock flow works in Go's sync.Mutex, let's break down the structure, or anatomy, of the mutex itself:

package sync

type Mutex struct {
    state int32
    sema  uint32
}

At its core, a mutex in Go has two fields: state and sema. They might look like simple numbers, but there's more to them than meets the eye.

The state field is a 32-bit integer that shows the current state of the mutex. It's actually divided into multiple bits that encode various pieces of information about the mutex.

Mutex structure

Let's make a rundown of state from the image:

• Locked (bit 0): Whether the mutex is currently locked. If it's set to 1, the mutex is locked and no other goroutine can grab it.
• Woken (bit 1): Set to 1 if any goroutine has been woken up and is trying to acquire the mutex. Other goroutines shouldn't be woken up unnecessarily.
• Starvation (bit 2): This bit shows if the mutex is in starvation mode (set to 1). We'll dive into what this mode means in a bit.
• Waiter (bit 3-31): The rest of the bits keep track of how many goroutines are waiting for the mutex.

The other field, sema, is a uint32 that acts as a semaphore to manage and signal waiting goroutines. When the mutex is unlocked, one of the waiting goroutines is woken up to acquire the lock.

Unlike the state field, sema doesn't have a specific bit layout and relies on runtime internal code to handle the semaphore logic.

Mutex Lock Flow

In the mutex.Lock function, there are two paths: the fast path for the usual case and the slow path for handling the unusual case.

func (m *Mutex) Lock() {
    // Fast path: grab unlocked mutex.
    if atomic.CompareAndSwapInt32(&m.state, 0, mutexLocked) {
        if race.Enabled {
            race.Acquire(unsafe.Pointer(m))
        }
        return
    }
    // Slow path (outlined so that the fast path can be inlined)
    m.lockSlow()
}

The fast path is designed to be really quick and is expected to handle most lock acquisitions where the mutex isn't already in use. This path is also inlined, meaning it's embedded directly into the calling function:

$ go build -gcflags="-m"

./main.go:13:12: inlining call to sync.(*Mutex).Lock
./main.go:15:14: inlining call to sync.(*Mutex).Unlock

FYI, this inlined fast path is a neat trick that utilizes Go's inline optimization, and it's used a lot in Go's source code.

When the CAS (Compare And Swap) operation in the fast path fails, it means the state field wasn't 0, so the mutex is currently locked.

The real concern here is the slow path m.lockSlow, which does most of the heavy lifting. We won't dive too deep into the source code since it requires a lot of knowledge about Go's internal workings.

I'll discuss the mechanism and maybe a bit of the internal code to keep things clear. In the slow path, the goroutine keeps actively spinning to try to acquire the lock, it doesn't just go straight to the waiting queue.

"What do you mean by spinning?"

Spinning means the goroutine enters a tight loop, repeatedly checking the state of the mutex without giving up the CPU.

In this case, it is not a simple for loop but low-level assembly instructions to perform the spin-wait. Let's take a quick peek at this code on ARM64 architecture:

TEXT runtime·procyield(SB),NOSPLIT,$0-0
    MOVWU   cycles+0(FP), R0
again:
    YIELD
    SUBW    $1, R0
    CBNZ    R0, again
    RET

The assembly code runs a tight loop for 30 cycles (runtime.procyield(30)), repeatedly yielding the CPU and decrementing the spin counter.

After spinning, it tries to acquire the lock again. If it fails, it has three more chances to spin before giving up. So, in total, it tries for up to 120 cycles. If it still can't get the lock, it increases the waiter count, puts itself in the waiting queue, goes to sleep, waits for a signal to wake up and try again.

Why do we need spinning?

The idea behind spinning is to wait a short while in hopes that the mutex will free up soon, letting the goroutine grab the mutex without the overhead of a sleep-wake cycle.

...

Full post is available here: Go Sync Mutex: Normal and Starvation Mode.

Ce qui précède est le contenu détaillé de. pour plus d'informations, suivez d'autres articles connexes sur le site Web de PHP en chinois!