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MySQL 条件查询语句有哪些?
一、 SELECT 条件查询
条件查询
条件查询就是在查询时给出 WHERE 子句, 在WHERE字句中可以使用如下运算符及关键字
==, !=, <>(不等于), <, >, <= >, >= BETWEEN ... AND IN(set) : 几个固定值 IS NULL , IS NOT NULL AND OR NOT: 非
二、 OR 条件查询
SELECT * FROM stu WHERE sid = "s_1001" OR sname="lisi";
三、 IN 条件查询
SELECT * FROM stu WHERE sid IN("s_1001", "s_1002", "s_1003"); // 查询符合条件的集合中 +--------+----------+------+--------+ | sid | sname | age | gender | +--------+----------+------+--------+ | s_1001 | liuYing | 35 | male | | s_1002 | chenger | 20 | male | | s_1003 | zhangsan | 15 | female | +--------+----------+------+--------+
四、 NOT IN 条件查询
SELECT * FROM stu WHERE sid NOT IN("s_1001", "s_1002", "s_1003"); // 查询符合条件不在集合中
查询结果
+--------+----------+------+--------+ | sid | sname | age | gender | +--------+----------+------+--------+ | s_1004 | wangwu | 23 | male | | s_1005 | liuYin | 35 | female | | s_1006 | zhaoliu | 70 | male | | s_1007 | sunQi | 15 | female | | s_1008 | zhouBa | 43 | male | | s_1009 | wuJiu | 85 | female | | s_1010 | zhengShi | 5 | male | +--------+----------+------+--------+
五、查询是否存在年龄为空 IS NULL
SELECT * FROM stu WHERE age IS NULL;
六、查询年龄不为空 IS NOT NULL
SELECT * FROM stu WHERE age IS NOT NULL;
七、使用 BETWEEN AND 或者 >= <= 查询 年龄 20 到 40 之间的数据
SELECT * FROM stu WHERE age BETWEEN 20 AND 40; SELECT * FROM stu WHERE age >= 20 AND age <= 40;
查询结果
+--------+---------+------+--------+ | sid | sname | age | gender | +--------+---------+------+--------+ | s_1001 | liuYing | 35 | male | | s_1002 | chenger | 20 | male | | s_1004 | wangwu | 23 | male | | s_1005 | liuYin | 35 | female | +--------+---------+------+--------+
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