Home  >  Article  >  Backend Development  >  我用swoole搭建一个websocket服务,关于访问IP的一点疑问

我用swoole搭建一个websocket服务,关于访问IP的一点疑问

WBOY
WBOYOriginal
2016-06-06 20:12:021323browse

安装swoole官方demo代码搭建一个websocket,
服务端代码:ws_server.php

<code>//创建websocket服务器对象,监听0.0.0.0:9502端口
$ws = new swoole_websocket_server("0.0.0.0", 9502);

//监听WebSocket连接打开事件
$ws->on('open', function ($ws, $request) {
    var_dump($request->fd, $request->get, $request->server);
    $ws->push($request->fd, "hello, welcome\n");
});

//监听WebSocket消息事件
$ws->on('message', function ($ws, $frame) {
    echo "Message: {$frame->data}\n";
    $ws->push($frame->fd, "server: {$frame->data}");
});

//监听WebSocket连接关闭事件
$ws->on('close', function ($ws, $fd) {
    echo "client-{$fd} is closed\n";
});

$ws->start();</code>

客户端代码:index.html

<code><script>
var wsServer = 'ws://127.0.0.1:9502';
var websocket = new WebSocket(wsServer);
websocket.onopen = function (evt) {
    console.log("Connected to WebSocket server.");
};

websocket.onclose = function (evt) {
    console.log("Disconnected");
};

websocket.onmessage = function (evt) {
    console.log('Retrieved data from server: ' + evt.data);
};

websocket.onerror = function (evt, e) {
    console.log('Error occured: ' + evt.data);
};
</script></code>

我用命令开启ws_server.php服务端,客户端文件index.html放在apache的web根目录下,我访问localhost,在console控制台能看到“Connected to WebSocket server.”等消息,证明访问成功
但是如果我把ws_server.php的监听ip改成其他(比如192.168.0.233:9502),然后在index.html相关代码改成wsServer = 'ws://192.168.0.233:9502';
访问为什么就不成功了呢?

回复内容:

安装swoole官方demo代码搭建一个websocket,
服务端代码:ws_server.php

<code>//创建websocket服务器对象,监听0.0.0.0:9502端口
$ws = new swoole_websocket_server("0.0.0.0", 9502);

//监听WebSocket连接打开事件
$ws->on('open', function ($ws, $request) {
    var_dump($request->fd, $request->get, $request->server);
    $ws->push($request->fd, "hello, welcome\n");
});

//监听WebSocket消息事件
$ws->on('message', function ($ws, $frame) {
    echo "Message: {$frame->data}\n";
    $ws->push($frame->fd, "server: {$frame->data}");
});

//监听WebSocket连接关闭事件
$ws->on('close', function ($ws, $fd) {
    echo "client-{$fd} is closed\n";
});

$ws->start();</code>

客户端代码:index.html

<code><script>
var wsServer = 'ws://127.0.0.1:9502';
var websocket = new WebSocket(wsServer);
websocket.onopen = function (evt) {
    console.log("Connected to WebSocket server.");
};

websocket.onclose = function (evt) {
    console.log("Disconnected");
};

websocket.onmessage = function (evt) {
    console.log('Retrieved data from server: ' + evt.data);
};

websocket.onerror = function (evt, e) {
    console.log('Error occured: ' + evt.data);
};
</script></code>

我用命令开启ws_server.php服务端,客户端文件index.html放在apache的web根目录下,我访问localhost,在console控制台能看到“Connected to WebSocket server.”等消息,证明访问成功
但是如果我把ws_server.php的监听ip改成其他(比如192.168.0.233:9502),然后在index.html相关代码改成wsServer = 'ws://192.168.0.233:9502';
访问为什么就不成功了呢?

设置成0.0.0.0代表监听所有地址来源的连接,所以可以进行连接。
而设置成192.168.0.233表示接受来自192.168.0.233这个主机的连接,你的本地主机不是192.168.0.233,连接自然不能建立。

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Previous article:查询哪个快呢Next article:弱问 php 如何更换版本?