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实例化php类的时候如何传参

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2016-06-06 19:49:011927browse

欢迎进入Linux社区论坛,与200万技术人员互动交流 >>进入 当我们实例化一个php类的时候,要怎么传递参数呢?这取决于该类的构造方法。 例: person.class.php ?php class person{ var $name; var $color; var $sex; var $age; function __construct($name,$

欢迎进入Linux社区论坛,与200万技术人员互动交流 >>进入

  当我们实例化一个php类的时候,要怎么传递参数呢?这取决于该类的构造方法。

  例:

  person.class.php

  

  class person{

  var $name;

  var $color;

  var $sex;

  var $age;

  function __construct($name,$age='',$sex='boy'){

  $this->name = $name;

  $this->age = $age;

  $this->sex = $sex;

  $this->color = 'yello';

  }

  function eat(){

  echo $this->name.'要吃饭';

  }

  function xinxi(){

  echo $this->name.' is '.$this->sex.' and age is '.$this->age.' fuse is '.$this->color;

  }

  }

  ?>

  son.php

  

  include('person.class.php');

  $son = new person('cuihua',25,'girl');//此处的参数传递要和类的构造方法里面的参数顺序对应

  //$son->xinxi();//cuihua is girl and age is 25 fuse is yello

  $son->name = '田妞';

  $son->eat();//田妞要吃饭

  ?>

实例化php类的时候如何传参

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