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PHP获取文件夹或目录的大小

Jun 06, 2016 pm 07:46 PM
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欢迎进入Linux社区论坛,与200万技术人员互动交流 >>进入 前两天在一个PHP项目中需要获取指定文件夹的大小,因为文件夹可能有很多子文件夹及子文件夹构成,所以在网上找了一圈没找到合适的,有的是不能正确获取多层嵌套的文件夹,有的是代码量太多,效率低。

欢迎进入Linux社区论坛,与200万技术人员互动交流 >>进入

  前两天在一个PHP项目中需要获取指定文件夹的大小,因为文件夹可能有很多子文件夹及子文件夹构成,所以在网上找了一圈没找到合适的,有的是不能正确获取多层嵌套的文件夹,有的是代码量太多,效率低。最后自己琢磨写了一个方法,效率还不错,而且可以获取到任意多层嵌套的文件夹大小。

  代码:

  

  function getFolderSize($dir){

  $count_size = 0;

  $count = 0;

  $dir_array = scandir($dir);

  foreach($dir_array as $key=>$filename){

  if($filename!="" && $filename!="."){

  if(is_dir($dir."/".$filename)){

  $new_foldersize = foldersize($dir."/".$filename);

  $count_size = $count_size+ $new_foldersize;

  }else if(is_file($dir."/".$filename)){

  $count_size = $count_size + filesize($dir."/".$filename);

  $count++;

  }

  }

  }

  return $count_size;

  }

  ?>

  调用:

  

  $folder_name = "textFolder";

  echo getFolderSize($folder_name);

  ?>

  上面getFolderSize这个函数返回的文件夹大小是以字节为单位的,为了更完善的实现功能,这里补充一个函数,将字节转换为KB,MB,GB,TB等单位。

  转换函数:

  

  function sizeFormat($bytes){

  $kb = 1024;

  $mb = $kb * 1024;

  $gb = $mb * 1024;

  $tb = $gb * 1024;

  if (($bytes >= 0) && ($bytes

  return $bytes . ' B';

  } elseif (($bytes >= $kb) && ($bytes

  return ceil($bytes / $kb) . ' KB';

  } elseif (($bytes >= $mb) && ($bytes

  return ceil($bytes / $mb) . ' MB';

  } elseif (($bytes >= $gb) && ($bytes

  return ceil($bytes / $gb) . ' GB';

  } elseif ($bytes >= $tb) {

  return ceil($bytes / $tb) . ' TB';

  } else {

  return $bytes . ' B';

  }

  }

  ?>

  最终调用:

  

  $folder_name = "textFolder";

  echo sizeFormat(getFolderSize($folder_name));

  ?>

PHP获取文件夹或目录的大小

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