ajax与PHP 传参问题
- WBOYOriginal
- 2016-06-06 19:42:30836browse
可以在PHP端把多个参数封装成一个对象。比如 $people['age'] = "21"; $people['gender'] = "male"; $people['phoneNum'] = "12345678"; 然后 echo json_encode($people); json_encode()函数的作用是把$people打包成一个JSON结构的对象。 然后在js端用eval（
可以在PHP端把多个参数封装成一个对象。比如
$people['age'] = "21";
$people['gender'] = "male";
$people['phoneNum'] = "12345678";
然后 echo json_encode($people);
json_encode()函数的作用是把$people打包成一个JSON结构的对象。
然后在js端用eval（）函数将JSON结构解析成一个对象，就可以用obj.age或者obj.phoneNum的形式调用PHP传过来的参数了。
详细的例子可以看这个：
http://www.cnblogs.com/elaron/archive/2010/11/16/1878369.html
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