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python通过装饰器检查函数参数数据类型的方法

WBOY
WBOYOriginal
2016-06-06 11:22:401314browse

本文实例讲述了python通过装饰器检查函数参数数据类型的方法。分享给大家供大家参考。具体分析如下:

这段代码定义了一个python装饰器,通过此装饰器可以用来检查指定函数的参数是否是指定的类型,在定义函数时加入此装饰器可以非常清晰的检测函数参数的类型,非常方便

代码如下:

def accepts(exception,**types):
    def check_accepts(f):
        assert len(types) == f.func_code.co_argcount, \
        'accept number of arguments not equal with function number of arguments in "%s"' % f.func_name
        def new_f(*args, **kwds):
            for i,v in enumerate(args):
                if types.has_key(f.func_code.co_varnames[i]) and \
                    not isinstance(v, types[f.func_code.co_varnames[i]]):
                    raise exception("arg '%s'=%r does not match %s" % \
                        (f.func_code.co_varnames[i],v,types[f.func_code.co_varnames[i]]))
                    del types[f.func_code.co_varnames[i]]
            for k,v in kwds.iteritems():
                if types.has_key(k) and not isinstance(v, types[k]):
                    raise exception("arg '%s'=%r does not match %s" % \
                        (k,v,types[k]))
            return f(*args, **kwds)
        new_f.func_name = f.func_name
        return new_f
    return check_accepts
def exmaple():
    @accepts(Exception,a=int,b=list,c=(str,unicode))
    def test(a,b=None,c=None)
        print 'ok'
    test(13,c=[],b='df')

希望本文所述对大家的Python程序设计有所帮助。

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