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python根据路径导入模块的方法

WBOY
WBOYOriginal
2016-06-06 11:19:381434browse

本文实例讲述了python根据路径导入模块的方法,分享给大家供大家参考。具体方法如下:

常规做法如下:

import sys 
sys.path.append('C:/full/path') 
from foo import util,bar 

而要直接通过路径

import imp 
util = imp.load_source('util', 'C:/full/path/foo/util.py') 

使用时使用util.method,此时并没有定义method
method = util.method后才可以直接用method

希望本文所述对大家的Python程序设计有所帮助。

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