Is the array name an address in C++?

yes. In C, the array name represents the first address of the memory address where the array elements are stored, so the array name itself is a pointer to the address of the first element of the array.

#Is the array name in C the address?

Answer: Yes

Detailed explanation:

In C, the array name represents the location where the array elements are stored The first address of the memory address. Therefore, the array name itself is a pointer to the address of the first element in the array.

When we declare an array, the compiler allocates a contiguous block of memory to store the array elements. The array name is a pointer to the beginning of the memory block.

We can access the elements in the array through the array name, just like using a pointer. For example, the following code will access the first element in the array arr:

<code class="cpp">int arr[10];
int* ptr = arr;
cout << *ptr; // 打印数组中第一个元素的值</code>

It should be noted that the type of the array name is a pointer type pointing to the array type element. For example, if arr is an array of int, then arr is of type int*.

Example:

<code class="cpp">int arr[5] = {1, 2, 3, 4, 5};
cout << arr << endl; // 打印数组的地址
cout << &arr[0] << endl; // 打印数组第一个元素的地址</code>

Output:

<code>0x10400
0x10400</code>

As shown in the example, the array name arr and the first element of the array The addresses of &arr[0] are the same, which further proves that the array name is an address.

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