What are the requirements for describing function return values ​​in the PHP function documentation specification?

In the PHP function documentation writing specifications, the return value description requirements are as follows: Syntax: @return mixed, indicating that the function can return any type of value. Special types: such as null, void, etc. indicate that the function does not return any value. Description: Use descriptive language to clearly describe the value returned by the function, avoid vague terminology, and specify the type and meaning of the return value. Multiple return values: Describe each return value in the order of the parameters in the parameter list.

PHP function documentation writing specifications: return value description

When writing PHP function documentation, the description of the return value is crucial important. Here's how to correctly describe a function return value:

Syntax:

@return mixed 返回值

Type:

• mixed means that the function can return any type of value.
• Special types Such as null, void, etc. indicate that the function does not return any value.

Description:

• Use descriptive language to clearly describe the value returned by the function.
• Avoid using vague terms (for example, "value") and instead be specific about the type and meaning of the return value.
• If the return value is an object or array, please describe the type of object or the structure of the array.
• If a function may return multiple values, describe each return value in an order that corresponds to the order of the parameters in the parameter list.

Example:

/**
 * 计算两个数字的和。
 *
 * @param int $a 第一个数字
 * @param int $b 第二个数字
 * @return int 数字之和
 */
function sum($a, $b): int
{
    return $a + $b;
}

/**
 * 获取用户信息。
 *
 * @param int $userId 用户 ID
 * @return array|null 用户信息数组，如果用户不存在则返回 null
 */
function getUser($userId): ?array
{
    $user = /* 从数据库中获取用户数据 */;

    return $user ?? null;
}

Practical case:

Write a function to calculate the area of ​​a circle .

/**
 * 计算圆的面积。
 *
 * @param float $radius 半径
 * @return float 面积
 */
function calculateCircleArea($radius): float
{
    return pi() * $radius ** 2;
}

Use this function:

$radius = 5;
$area = calculateCircleArea($radius);

echo "圆的面积：$area 平方单位";

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