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The function pointer is passed as a parameter in C: the function pointer is passed as a constant pointer, a copy is created during the transfer process, the received function formal parameter points to the copy, and the dereferenced copy can call the underlying function.
C function pointer parameter passing mechanism
In C, function pointers can be passed to functions as parameters. This allows us to dynamically encapsulate function calls in a callable object.
Passing mechanism
When passing a function pointer as a parameter, the following mechanism is followed:
Practical case
The following is an example of a C program that uses function pointers as parameters:
#include <iostream> // 一个接受函数指针作为参数的函数 void callFunction(void (*function)()) { function(); // 调用通过函数指针传递的函数 } // 一个示例函数 void printMessage() { std::cout << "Hello, world!" << std::endl; } int main() { // 定义一个函数指针指向 printMessage 函数 void (*printMessageFunction)() = &printMessage; // 将函数指针传递给 callFunction 函数 callFunction(printMessageFunction); return 0; }
In the above example,callFunction
The function accepts a function pointer (void (*function)()
as a parameter, which points to a function that does not accept parameters and does not return a value. main
Function A function pointer named printMessageFunction
is defined that points to the printMessage
function, which is then passed to the callFunction
function. The callFunction function dereferences the function pointer (
function()) and calls the underlying
printMessage function to output "Hello, world!"
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