How to write a palindrome number using c language code

In C language, write a palindrome number through the following steps: 1. Reverse the input integer bit by bit and store it in the inversion variable; 2. Compare whether the original integer and the inverted integer are equal; 3. Based on the comparison As a result, determine whether the input integer is a palindrome.

How to write a palindrome number using C language

The palindrome number is a left-to-right and a right-to-right Integers that read the same to the left. For example, 121 and 909 are palindromes, but 123 and 456 are not.

C language code implementation

The following C language code shows how to check whether an integer is a palindrome:

<code class="c">#include <stdio.h>

int main() {
    int num, reversed_num = 0, reminder;

    printf("输入一个整数：");
    scanf("%d", &num);

    int original_num = num;

    // 反转数字
    while (num != 0) {
        reminder = num % 10;
        reversed_num = reversed_num * 10 + reminder;
        num /= 10;
    }

    // 检查原数字和反转后的数字是否相等
    if (original_num == reversed_num) {
        printf("%d 是回文数。\n", original_num);
    } else {
        printf("%d 不是回文数。\n", original_num);
    }

    return 0;
}</code>

Code description

1. Enter an integer: First, enter an integer from the user and store it in the num variable.
2. Initialize the reversed number: reversed_num The variable is used to store the reversed version of the input number, which is initially initialized to 0.
3. Reverse numbers: Use a while loop to traverse each digit of num from right to left and add its reverse to reversed_num middle.
4. Compare numbers: Compare the original number original_num and the reversed number reversed_num. If they are equal, num is a palindrome number.
5. Output result: Based on the comparison result, print out whether num is a palindrome number.

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