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HomeBackend DevelopmentGolangDeadlock - all goroutines are sleeping (even using wait groups)

死锁 - 所有 goroutine 都处于睡眠状态(即使使用等待组)

php editor Xiaoxin is here to introduce to you a common concurrent programming problem-deadlock. Deadlock means that all goroutines have entered the sleep state and cannot continue to execute even if mechanisms such as waiting groups are used. In this case, all goroutines are unable to move forward, causing the program to fall into an infinite waiting state. In concurrent programming, it is very important to avoid deadlock, and we need to understand its causes and solutions to ensure the normal operation of the program.

Question content

I'm learning go concurrency and I want two go routines to continue communicating with each other while passing updated values ​​through a channel. One adds 2 and the other subtracts 1. The code and output are as follows:

What's wrong with this code?

package main

import (
    "fmt"
    "sync"
    "time"
)

var wg sync.waitgroup

func addtwo(r chan int, e chan int) {
    val := <-r
    fmt.println("at recieved: ", val)
    time.sleep(1 * time.second)
    e <- val + 2
}

func subtractone(r chan int, e chan int) {
    val := <-r
    fmt.println("so recieved: ", val)
    time.sleep(1 * time.second)
    e <- val - 1
}

func main() {
    ch := make(chan int)
    ch2 := make(chan int)

    wg.add(1)
    go addtwo(ch, ch2)

    wg.add(1)
    go subtractone(ch2, ch)

    ch <- 1
    wg.wait()

}

Output:

AT Recieved:  1
SO Recieved:  3
fatal error: all goroutines are asleep - deadlock!

goroutine 1 [semacquire]:
sync.runtime_Semacquire(0x4b2de8?)
    /usr/lib/go-1.18/src/runtime/sema.go:56 +0x25
sync.(*WaitGroup).Wait(0x0?)
    /usr/lib/go-1.18/src/sync/waitgroup.go:136 +0x52
main.main()

Then it exits.

Why doesn't the goroutine always swap values, even if I don't call wg.done() in the goroutine?

Solution

Both goroutines you start only receive one value and send one value, and then end. From there, there is only the main goroutine, which is blocked at wg.wait() because you never called wg.done().

You forgot to use an (n infinite) loop:

func addtwo(r chan int, e chan int) {
    for {
        val := <-r
        fmt.println("at recieved: ", val)
        time.sleep(1 * time.second)
        e <- val + 2
    }
}

func subtractone(r chan int, e chan int) {
    for {
        val := <-r
        fmt.println("so recieved: ", val)
        time.sleep(1 * time.second)
        e <- val - 1
    }
}

With this change, your application will run forever and the output will be:

AT Recieved:  1
SO Recieved:  3
AT Recieved:  2
SO Recieved:  4
AT Recieved:  3
SO Recieved:  5
AT Recieved:  4
....

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