


php editor Zimo will share with you how to let golang distinguish XML elements with namespaces and without namespaces. When dealing with XML data, namespace is an important concept that can help us better organize and distinguish different XML elements. This article will introduce how to use golang's xml package to parse and process XML elements with and without namespaces, and provide some sample codes for practical applications. Whether you are a beginner or an experienced developer, you will gain valuable knowledge and tips from this article. Let’s explore this fun and practical topic together!
Question content
Suppose I have the following xml data:
<image> <url> http://sampleurl.com </url> </image> <itunes:image url="http://sampleitunesurl.com" /> //xmldata
I use this structure to decode it:
type response struct { xmlname xml.name `xml:"resp"` image []struct { url string `xml:"url"` } `xml:"image"` itunesimage struct { url string `xml:"url,attr"` } `xml:"http://www.itunes.com/dtds/podcast-1.0.dtd image"` }
I have this code:
var resp Response err := xml.Unmarshal([]byte(xmlData), &resp) if err != nil { fmt.Printf("Error decoding XML: %s\n", err) return } for _, img := range resp.Image{ if img.URL != "" { //<image>, not <itunes:image> } }
Processing decoding
The problem I'm having is that it looks like image []struct
thinks <image></image>
and <image></image>
elements because they all have "images". To filter out <image>, the approach I used was to have everyone in the <code>image []struct
check if their url
was an empty string ( Because for <image> its <code>url
is an attribute).
Another approach is to write my own unmarshal
function to differentiate between xml elements with and without itunes
namespace. Basically I want image []struct
to save only the element <image></image>
I wonder if go has some built-in functionality to differentiate? Or do I have to write code to filter out <image></image>
?
Solution
Please note that field order is important. itunesimage
has a more specific tag, so it should come before image
.
package main import ( "encoding/xml" "fmt" ) func main() { type response struct { xmlname xml.name `xml:"resp"` itunesimage struct { url string `xml:"url,attr"` } `xml:"http://www.itunes.com/dtds/podcast-1.0.dtd image"` image []struct { url string `xml:"url"` } `xml:"image"` } xmldata := ` <resp xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd"> <image> <url>http://sampleurl.com</url> </image> <itunes:image url="http://sampleitunesurl.com/" /> </resp> ` var resp response err := xml.unmarshal([]byte(xmldata), &resp) if err != nil { fmt.printf("error decoding xml: %s\n", err) return } fmt.printf("itunesimage: %v\n", resp.itunesimage) fmt.printf("images: %v\n", resp.image) }
If you only need the <image></image>
in the image/url
tag, you can define the response
structure like this:
type response struct { xmlname xml.name `xml:"resp"` image []string `xml:"image>url"` }
Regarding the general question in the title (how to make golang differentiate between xml elements with and without namespaces?), you can capture the element name using a field called xmlname
, and check that field Member of space
. See demo below:
package main import ( "encoding/xml" "fmt" ) func main() { type response struct { xmlname xml.name `xml:"resp"` image []struct { xmlname xml.name url string `xml:"url"` } `xml:"image"` } xmldata := ` <resp xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd"> <image> <url>http://sampleurl.com</url> </image> <itunes:image> <url>http://sampleitunesurl.com/</url> </itunes:image> </resp> ` var resp response err := xml.unmarshal([]byte(xmldata), &resp) if err != nil { fmt.printf("error decoding xml: %s\n", err) return } for _, img := range resp.image { fmt.printf("namespace: %q, url: %s\n", img.xmlname.space, img.url) } }
The output of the above demonstration is:
namespace: "", url: http://sampleUrl.com namespace: "http://www.itunes.com/dtds/podcast-1.0.dtd", url: http://sampleItunesUrl.com/
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