Use two generics to implement the interface

php editor Xinyi will introduce to you the method of using two generics to implement the interface. Generics are a feature that enables the use of type parameters in programming languages, which can increase the flexibility and reusability of code. When implementing an interface, we can use generics to specify the type parameters in the interface, so that different data types can be used in different scenarios. This method can make our code more versatile and scalable and improve development efficiency. In this article, we will explain in detail how to use two generics to implement the interface, and give sample code for your reference.

Question content

I have a task for my homework but I can't get over it.

The code of the transformer interface is as follows:

public interface transformer<from, to> {
    to transform(from value);
}

So far, the code for the personsubscribertransformer class looks like this:

public class PersonSubscriberTransformer<FROM, TO> implements Transformer {
    private Predicate<Person> predicate;
    public PersonSubscriberTransformer(Predicate<Person> predicate) {
        this.predicate = predicate;
    }
    @Override
    public Object transform(Object value) {
        return null;
    }
  }

The parameters of the

transform method should be list0833d296851a1e081f2175a4cbfa7135 and it should return a list2dd1b1a23a493c1b50630f436ee0c708. When I change the parameters, I get an error message saying that I should pull the method to the transformer interface.

What is the solution to implement this method in the right way?

Workaround

Based on the expected signature of transform, from should be list0833d296851a1e081f2175a4cbfa7135 and to should be list<subscriberphpcngt phpcn. Classes themselves should not be generic.

public class PersonSubscriberTransformer implements Transformer<List<Person>, List<Subscriber>> {
    // constructor...
    
    @Override
    public List<Subscriber> transform(List<Person> persons) {
        // complete this method...
        return null;
    }
}

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