php editor Apple will introduce you to an important note in this article: "Do not accept repeated input from stdin." In programming, we often use stdin as an input source, but repeated input may cause errors or unpredictable behavior in the program. Therefore, we need to pay attention to avoiding duplication of input when using stdin to ensure the normal operation of the program. In the following article, we will explore this problem in detail and provide some solutions and practical suggestions to help readers better handle duplicate situations of stdin input.
Question content
I have a contrived program whose goal is to echo text on standard input (as many times as necessary) and exit after 10 seconds. code show as below:
package main import ( "bufio" "fmt" "os" "time" ) func main() { input := make(chan string) abort := make(chan bool) // exit after 10 sec go func() { time.Sleep(10 * time.Second) abort <- true }() go func() { cmd := bufio.NewScanner(os.Stdin) for cmd.Scan() { input <- "<- " + cmd.Text() } }() select { case <-abort: fmt.Println("exiting") return case cmd := <-input: fmt.Println(cmd) } }
The problem is when I enter the first line of text, it echoes to stdout and the program exits. I want to enter as many commands as possible in 10 seconds.
What did i do wrong?
Workaround
The abort channel is closed after 10 seconds, which allows the first selection case (
func main() { input := make(chan string) abort := make(chan bool) // exit after 10 sec go func() { time.Sleep(10 * time.Second) close(abort) // Close the channel after 10 seconds }() go func() { cmd := bufio.NewScanner(os.Stdin) for cmd.Scan() { input <- "<- " + cmd.Text() } }() for { select { case <-abort: fmt.Println("closing connection") return case cmd := <-input: fmt.Println(cmd) } } }'
I used "for" to replace the outer select statement with an infinite loop After the 10 second timeout, I close the abort channel using a close(abort) statement. This tells the select statement that a timeout has occurred and execution of the first case (
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