How to correctly replace strings in golang with "greedy principle"?

Question content

I tried to mask the string, but something went wrong

The reproducible code is as follows and requires all old and new pairs, how to get col1 instead of col0b?

package main

import (
    "fmt"
    "strings"
)

func main() {
    r := strings.NewReplacer("a", "col0", "ab", "col1")
    s := "ab"
    fmt.Println(r.Replace(s))
}

I hope that the string can be replaced using the maximum length or greedy principle

Correct answer

According to documentation, NewReplacer's replacement is as per their The strings are executed in the order they appear in the target, with no overlapping matches, so it will always follow the basis of the first match. If allowed, I think you could fix this by reorganizing the replacement pairs so that the longer string ("ab"-"col1") is placed inside the shorter string ( "a","col0")before

package main

import (
    "fmt"
    "strings"
)

func main() {
    r := strings.NewReplacer("ab", "col1", "a", "col0")
    s := "ab"
    fmt.Println(r.Replace(s))
}

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