Backend DevelopmentGolangHow to write a regular expression for the last occurrence of a single space in Go?How to write a regular expression for the last occurrence of a single space in Go?
我想用其他内容替换字符串中的最后一个空格。如何在 Golang 中为最后一个空格编写正则表达式？到目前为止我只发现 \s+ 匹配所有空格
正确答案
您可以使用此正则表达式：
\s(\s*)$
这匹配一个空白字符，后跟任何非白色字符 (\s*)，直到字符串末尾 ($)。
您可以像这样替换最后一个空白字符：
s := "this is a string" re := regexp.MustCompile(`\s(\S*)$`) s2 := re.ReplaceAllString(s, "-$1") // "this is a-string"
$1 是捕获的组 (\s*)，保留空格后的其余内容。只需将“-”字符替换为您想要替换空白字符的任何字符即可。
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