


我有一个来自 API 的 JSON 响应,如下所示:
{ "1091500": { "data": { "price_overview": { "final_formatted": "$59.99" } } } }
当我解组并访问我需要的价格值时,我的结构工作正常。
price.AppID.Data.PriceOverview.FinalFormatted
此处的结构:
type SteamApp struct { AppID struct { Data struct { PriceOverview struct { FinalFormatted string `json:"final_formatted"` } `json:"price_overview"` } `json:"data"` } `json:"1091500"` }
我正在尝试解决的是顶级密钥“1091500”。这是由单独函数生成的值,实际上是获取上述数据所需的搜索词。话虽这么说,它是动态的,并且是在运行时通过单独的 API 调用发现的。因为您需要结构中的 JSON 标记,所以我正在努力想出一种方法来概括它。
到目前为止,最好的方法是找到一个以不同方式返回数据的不同 API,但我还没有找到。我还考虑过找到一种方法来“跳过”初始部分,因为我有正确的数据,这只是“阅读”它的问题。预先感谢您,我希望我能很好地解释自己。
正确答案
分两步解组。首先进入映射,然后进入结构类型。您可以通过实现 json.Unmarshaler 自动执行此操作:
package main import ( "encoding/json" "fmt" ) var j = []byte(`{ "1091500": { "data": { "price_overview": { "final_formatted": "$59.99" } } } }`) func main() { var t T err := json.Unmarshal(j, &t) fmt.Println(err) fmt.Printf("%+v\n", t) } type T struct { AppID string `json:"-"` PriceOverview struct { FileFormatted string `json:"final_formatted"` } `json:"price_overview"` } func (t *T) UnmarshalJSON(b []byte) error { var m map[string]struct { Data json.RawMessage } err := json.Unmarshal(b, &m) if err != nil { return err } type T_ T // prevent recursion var t_ T_ for appID, x := range m { err := json.Unmarshal(x.Data, &t_) if err != nil { return err } *t = T(t_) t.AppID = appID break } return nil }
在操场上尝试一下:https://www.php.cn/link/8571ddcc1c64ca1fa11891d899cab05d一个>
我假设数据属性只是噪音并使其透明。如果我弄错了,请使用 map[string]json.RawMessage 并将数据字段添加到类型 T。
如果您也想自动编组为相同的格式,请实现 json.Marshaler还有:
func (t T) MarshalJSON() ([]byte, error) { type T_ T // prevent recursion m := map[string]struct { Data T_ `json:"data"` }{ t.AppID: {Data: T_(t)}, } return json.Marshal(m) }
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