How to run "go test" in the parent directory of multiple go modules and return non-zero on error

Question content

Look at this directory structure:

/root
    /hoge
        go.mod
        go.sum
        main.go
        /test
           main_test.go
           /unit
              sub_test.go
    /fuga
        go.mod
        go.sum
        main.go
        /test
           main_test.go

You can run the test using the following code, but it will always return exit code 0 if it fails.

find . -name go.mod -execdir go test ./... \;

Is there a way to return a non-zero value if it fails?

Correct Answer

Use this command:

find . -name go.mod -execdir go test ./... -- {} +

findCommand Manual About -execdir command{} ：

If any call using the " " form returns a non-zero value as the exit status, find returns a non-zero exit status. If find encounters an error, it sometimes causes an immediate exit, so some pending commands may not run at all.

But go test does not require matching files in the find command. In fact, it will fail like this:

$ go test ./... go.mod
no required module provides package go.mod; to add it:
    go get go.mod

Fails because go.mod is interpreted as a package.

The solution is to add the terminator -- before {} . See Command Line Flag Syntax:

Flag parsing stops before the first non-flag parameter ("-" is a non-flag parameter) or after the terminator "--".

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