How do I change the instance type in an EC2 launch template using the AWS SDK?

Question content

I want to change something in the launch template, such as the instance type. This means creating a new version while doing so.

I have browsed the SDK documentation for Go and Python. Neither seems to have parameters that allow me to achieve the same goal.

I am referring to these: Go functions, Python functions

Please help me...

Correct answer

ec2 Launch templates are immutable. If you need to modify the current launch template version, you must create a new version.

The following is an example of using AWS SDK v2 to create a new version and set it as the default version.

Install these two packages:

"github.com/aws/aws-sdk-go-v2/service/ec2"
ec2types "github.com/aws/aws-sdk-go-v2/service/ec2/types"

Assuming you created an aws configuration:

func createLaunchTemplateVersion(cfg aws.Config) {
    ec2client := ec2.NewFromConfig(cfg)
    template := ec2types.RequestLaunchTemplateData{
        InstanceType: ec2types.InstanceTypeT2Medium}
    createParams := ec2.CreateLaunchTemplateVersionInput{
        LaunchTemplateData: &template,
        LaunchTemplateName: aws.String("MyTemplate"),
        SourceVersion:      aws.String("1"),
    }
    outputCreate, err := ec2client.CreateLaunchTemplateVersion(context.Background(), &createParams)
    if err != nil {
        log.Fatal(err)
    }
    if outputCreate.Warning != nil {
        log.Fatalf("%v\n", outputCreate.Warning.Errors)
    }
    // set the new launch type version as the default version
    modifyParams := ec2.ModifyLaunchTemplateInput{
        DefaultVersion:     aws.String(strconv.FormatInt(*outputCreate.LaunchTemplateVersion.VersionNumber, 10)),
        LaunchTemplateName: outputCreate.LaunchTemplateVersion.LaunchTemplateName,
    }
    outputModify, err := ec2client.ModifyLaunchTemplate(context.Background(), &modifyParams)
    if err != nil {
        log.Fatal(err)
    }
    fmt.Printf("default version %d\n", *outputModify.LaunchTemplate.DefaultVersionNumber)
}

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