Write a Java program to solve the solution of the quadratic equation: ax^2 + bx + c

Use java to write a program to solve a quadratic equation: aX2 bX c 0

The following program passed the jdk5.0 test

import java.util.Scanner;

public class Test {

//Solution to quadratic equation of one variable

private static X fx (int a,int b,int c) throws Exception{

X x = new X();

double m = b*b - 4*a*c;

if(m>=0){

x.x1=(-1*b Math.sqrt(m))/(2*a);

x.x2=(-1*b-Math.sqrt(m))/(2*a);

return x;

}

else throw new Exception（＂No solution＂）；

}

public static void main(String[] args) {

try{

//Input parameters a, b, c

Scanner cin=new Scanner(System.in);

System.out.print(＂a=＂);

int a = cin.nextInt();

System.out.print(＂b=＂);

int b = cin.nextInt();

System.out.print("c=＂");

int c = cin.nextInt();

//calculate

X x=fx(a,b,c);

//show

System.out.println(＂\n1x1=＂x.x1 ＂\nx2=＂x.x2);

}catch(Exception e){

System.out.println(e.getMessage());

}

}

}

//Quadratic equation solution set packaging class

class X{

double x1;

double x2;

}

Write a program in Java to solve a quadratic equation of one variable: aX2 bX c 0

public static main(String[] arg0){

if(arg0== null || arg0.length == 0){

System.out.println（＂Please enter parameters: a, b, c＂）;

System.exit(0);

}

for(int i=0;i

try {

Float.parseFloat(arg0[i]);

} Catch(Exception e){

System.out.println("Please enter a number");

System.exit(0);

}

}

float a = Float.parseFloat(arg0[0]);

float b = 0;

float c = 0;

if(arg0.length >= 2){

b = Float.parseFloat(arg0[1]);

}

if(arg0.length >= 3){

c = Float.parseFloat(arg0[2]);

}

float tmp = b*b - 4*a*c;

if(tmp

System.out.println("x has no real roots");

System.exit(0);

}

if(a==0 & b==0 & c==0){

System.out.println("x has any real root");

System.exit(0);

}

float result = (-1)*b/(2*a);

if(tmp == 0){

System.out.println("x1=x2=＂ result);

System.exit(0);

}

float x1 = ((-1)*b java.lang.Math.sqrt(tmp))/(2*a);

float x2 = ((-1)*b-java.lang.Math.sqrt(tmp))/(2*a);

System.out.println("x1=" x1);

System.out.println("x2=" x2);

}

Java programming the root of the cubic equation a x x x b x x c x d 0

import java.io.*;

public class Test1

{

public static void main(String[] args) throws IOException

{

double a,b,c,d,x,y;

System.out.println ("Solution to cubic equation of one variable: y=ax3 bx2 cx d");

System.out.println ("Please enter a value:");

BufferedReader in1=new BufferedReader(new InputStreamReader(System.in));

a=Double.parseDouble(in1.readLine());

System.out.println("Please enter b value:");

BufferedReader in2=new BufferedReader(new InputStreamReader(System.in));

b=Double.parseDouble(in2.readLine());

System.out.println ("Please enter the c value:");

BufferedReader in3=new BufferedReader(new InputStreamReader(System.in));

c=Double.parseDouble(in3.readLine());

System.out.println ("Please enter the d value:");

BufferedReader in4=new BufferedReader(new InputStreamReader(System.in));

d=Double.parseDouble(in4.readLine());

System.out.println("Please enter x value:");

BufferedReader in5=new BufferedReader(new InputStreamReader(System.in));

x=Double.parseDouble(in5.readLine());

y=a*Math.pow(x, 3) b*Math.pow(b,2) c*x d;

System.out.println("y value is:" y);

}

}

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