Which operator has the highest precedence in Go language?

The operator with the highest precedence in Go language is the bracket operator ().

In the Go language, the parentheses operator is mainly used to change the priority of operators by placing expressions that require priority operations within parentheses. The bracket operator changes the order in which an expression is evaluated so that it is evaluated before other operators and the result is used as the operand of other operators.

The following is a specific code example that shows the usage of the bracket operator and its priority in the operation process:

package main

import "fmt"

func main() {
    var result int

    // 示例1：括号运算符优先级
    result = 2 + 3 * 4
    fmt.Println("2 + 3 * 4 =", result) // 输出：14

    result = (2 + 3) * 4
    fmt.Println("(2 + 3) * 4 =", result) // 输出：20

    // 示例2：括号运算符对布尔运算的影响
    var flag1, flag2 bool
    flag1 = true
    flag2 = false

    result = (5 < 10) && flag1 || flag2
    fmt.Println("(5 < 10) && flag1 || flag2 =", result) // 输出：true

    result = 5 < 10 && (flag1 || flag2)
    fmt.Println("5 < 10 && (flag1 || flag2) =", result) // 输出：true
}

In Example 1, we perform an addition and Multiplication expressions are evaluated. Since the multiplication operator has higher precedence than the addition operator, without parentheses, the multiplication operation occurs first. The output proves this.

And in Example 2, we show the impact of the bracket operator on Boolean operations. Since the parentheses operator has higher precedence than the logical AND (&&) and logical OR (||) operators, the logical AND operation will be evaluated before the logical OR operation without adding parentheses. By outputting the results, we can verify the impact of the bracket operator on Boolean operations.

To sum up, the bracket operator () has the highest priority in Go language. By using the parentheses operator appropriately, we can change the order in which expressions are evaluated to meet specific computing needs.

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