正则表达式
if (eregi("^[_.0-9a-z-]+@([0-9a-z][0-9a-z-]+.)+[a-z]$",$email)) {
echo "您的 E-Mail 通过初步检查";
}
?>
在这句话里,首先是应用了一个eregi函数,这个函数还算好理解。随便找本书,就能给你一段解释:
语法: int ereg(string pattern, string string, array [regs]);
返回值: 整数/数组
本函数以 pattern 的规则来解析比对字符串 string。
比对结果返回的值放在数组参数 regs 之中,regs[0] 内容就是原字符串 string、regs[1] 为第一个合乎规则的字符串、regs[2] 就是第二个合乎规则的字符串,余类推。若省略参数 regs,则只是单纯地比对,找到则返回值为 true。
而不太好理解的就是前面的这段正则表达式了:^[_.0-9a-z-]+@([0-9a-z][0-9a-z-]+.)+[a-z]$
在这段正则表达式中,"+"表示前面的字符串连续出现一个或多个;"^"表示下一个字符串必须出现在开头,"$"表示前一个字符串必须出现在结尾;
"."也就是".",这里""是转义符;""表示前面的字符串可以连续出现2-3次。"()"表示包含的内容必须同时出现在目标对象中。"[_.0-9a-z-]"表示包含在"_"、"."、"-"、从a到z范围内的字母、从0到9范围内的数字中的任意字符;
这样一来,这个正则表达式可以这样翻译:
"下面的字符必须在开头(^)"、"该字符必须包含在"_"、"."、"-"、从a到z范围内的字母、从0到9范围内的数字中([_.0-9a-z-])"、"前面这个字符至少出现一次(+)"、@、"该字符串由一个包含在从a到z范围内的一个字母、从0到9范围内的数字中的字符开头,后面跟至少一个包含在"-"、从a到z范围内任何一个字母、从0到9范围内任何一个数字中的字符,最后以.结束(([0-9a-z][0-9a-z-]+.))"、"前面这个字符至少出现一次(+)"、"从a到z范围内的字母出现2-3次,并以它结束([a-z]$)"
很繁杂是吧,对了,正因为这样,人们才使用正则表达式。

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