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The arithmetic mean is the sum of a set of numbers divided by the number of numbers in the set.
n The average of the numbers x1, x2,. . .,xn is x. If each observation is increased by p, then the mean of the new observations is (x p).
#n Numbers x1, x2, . . .,xn is x. If each observation is reduced by p, then the mean of the new observations is (x - p).
n Numbers x1, x2, . . .,xn is x. If each observation is multiplied by a nonzero number p, the mean of the new observations is px.
#n average of em> numbers x1, x2, . .,xn is x. If each observation is divided by a nonzero number p, the mean of the new observations is (x/p).
Type 1: Direct average
Given array and number of elements
Input- 1,2,3,4,5,6,7,8,9
Output- 5
Explanation- To calculate the arithmetic mean of all numbers, first add all the numbers, then create a variable responsible for the arithmetic mean and put the addition/size into the variable like armean .
#include<iostream> using namespace std; int main(){ int n, i, sum=0; int arr[]={1,2,3,4,5,6,7,8,9}; n=9; for(i=0; i<n; i++) { sum=sum+arr[i]; } int armean=sum/n; cout<<"Arithmetic Mean = "<<armean; }
Type 2: Given range and number of elements present.
Given three integers X, Y and N. Find the arithmetic mean of N between logical X and Y.
N terms in an arithmetic series (the number of terms between #- Explanation
Suppose X1
, X2, X3
, X4
……Xn is the arithmetic mean between N two given numbers X and Y.
Then X, X1, X2, X3, Y will be in an arithmetic series. Now Y = the (N 2)th term of the arithmetic series. Find the (N 2)th term of the arithmetic series where d is the tolerance
X= first and Y= last terms.Therefore the tolerance d is given by.
22 24 26 28 30 32 34We have the value of A and the value of the tolerance (d), now we can find all N arithmetic means between X and Y. Example
Y = X + (N + 2 - 1)d Y - X = (N + 1)dOutput
d = (Y - X) / (N + 1)
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