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HomeBackend DevelopmentPHP Tutorial用PHP MySql编写聊天室_PHP

大家好!好久没有看到大家了,上次写了用PHP的通过文件操作的聊天室,当然是漏洞百出的,而且每一次刷新屏幕都很糟糕的!我想了好久,是不是能有一种方法不要刷新,就能取得发言的信息了?多用一个框架就能实现这个效果了,即多用一个框架我们称为getmsg,我们让getmeg去取得信息而且保证每一次取得的信息是最新的,就是上次取得的发言就不要了,上次我编的就是每一次取得信息都是重复的,这样效果不好。
我的设计思想是:每一次发言,都把它提交到服务器上,然后保存到一个数据库里,每格几秒钟getmsg就去服务器上取得 最新发言数据,并保证上次取得的发言就不要取下来了,然后把取下来的发言叠加到一个专门显示发言的窗口(listmsg)去。这样我们就感觉listmsg窗口不会有重刷新的感觉而且,只是看到发言信息不断加进去,这样就有很好的效果,
怎样在一个框架把信息加到另个框架去了?用JavaScript就可以实现这个想法的:

当然你得在mysql里建两个表,一个表用于保存发言信息,一个表用于保存几个在线的,在列在线人数时,我们让它每个60秒刷新一次,并把一分钟以前的发言删掉,并看某个发言人是不是很长时间没发言了,是的话,就删掉他,
由于表的子段很简单,在这里就不要写出来了,看程序就会知道了。这个程序在网上网下测试的效果都很好!
表的名字是:chat和chat_getmsg

if(!isset($username))
$username="guest";
$conid=mysql_connect("localhost","yourcounter","password");
mysql_select_db("yourdadabase",$conid);
$dstr=date("YmdHis");
$sql="insert chat_getmsg (username,shijian) values ('$username','$dstr')";
mysql_query($sql,$conid);
$sql="update chat_getmsg set shijian='$dstr' where username='$username'";
mysql_query($sql,$conid);
mysql_close($conid);
?>


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