In this tutorial we have to write an algorithm to find a way to pass the assignment without being discovered by the proctor. Each student must submit assignments to the proctor. Student A's assignment is given to Student B, so Student B must return/pass the assignment to Student A without the proctor noticing.
All students are sitting in the queue. We need to find a way to pass the assignment back to student A without getting caught. The various requirements for which they can pass the assignment are as follows -
Student A (at index i) can pass the assignment to the neighbors at index (i- 1) and (i 1)
Students can submit, accept, or hold assignments.
The proctor is monitoring all students in index [il, rl].
When students are within range of the proctor, they cannot send or receive assignments.
Students cannot send or receive assignments while they are under the supervision of a proctor. p>
If students retain assignments within this range, proctors will not detect them.
We are given four inputs p, q, r, s, where p is the total number of students, q is the total number of steps monitored by the invigilator from il to rl, and c is The position of student A, d is the position of student A. Student B's position.
Each step (q) has three inputs -
The total time the proctor monitors the given range.
In the containment range on the far left, the invigilator is watching.
In the included range on the far right, the invigilator is watching. , watching.
Requires an output sequence of 3 words: "left", "right" and "hold", indicating the student's activity (if they are watching) through the assignment (left/right) or Keep it. For example,
Steps
Input
8 3 2 7 1 4 6 2 1 8 3 5 6
Output
Right Keep Right Right Right Right
Explanation
Following these instructions, the assignment will be transferred from the student at index 2 to the student at index 7 without being captured.
Input
5 1 1 3 1 2 5
Output
Keep Right Right
Explanation
Follow these instructions , the assignment will be transferred from the student at index 1 to the student at index 3 without being captured.
Close to a solution
In a given instance, if the proctor is monitoring within the scope, either the student currently doing the assignment or the student to whom the assignment is being sent, Then the student will remain with him on that task. Otherwise, he passes the ball to an adjacent student in the direction of the final goal.
Example
#include <bits/stdc++.h> using namespace std; void solve(int p, int q, int r, int s, long t[], int l[], int ar[]){ int dir; string val; if (r < s) { dir = 1; val = "Right"; } else { dir = -1; val = "Left"; } string answer = ""; int i = 0, current = r; long tim = 1; while (1) { if (i < q && tim == t[i]) { if ((current >= l[i] && current <= ar[i]) || (current + dir >= l[i] && current + dir <= ar[i])) { answer += "Keep\n"; tim++; i++; continue; } i++; } current += dir; answer += val+"\n"; tim++; if (current == s) break; } cout << answer << endl; } int main(){ int p = 8, q = 3, r = 2, s = 7; long t[q + 2] = { 1,2,3 }; int l[q + 2] = { 4,1,5 }; int ar[q + 2] = { 6,8,6 }; solve(p, q, r, s, t, l, ar); return 0; }
Output
Right Keep Right Right Right Right
Conclusion
In this tutorial, we learned to write an algorithm to find an algorithm that works without being proctored Personnel found the case through the assignment method as well as the C code. We can also write this code in java, python and other languages. The above algorithm is an important algorithm for competitive coding competitions. This question contains a real-life problem that we solved through C code. We hope you found this tutorial helpful.
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