Why are string literals stored in string constant pool in Java?

There are two ways to create a String object in Java

• Use the new operator

String str = new String("Tutorials Point");

• By using string literals

String str = "Tutorials Point";

Whenever we call new String() in Java, it will create an object in the heap memory and the string literal will go into the string constant pool ( SCP).

For objects, the JVM uses SCP, which is for efficient memory management in Java. Unlike other Java objects, they do not manage String objects in the heap area, but introduce a String constant pool. An important feature of the String constant pool is that if there is already a String constant in the pool, the same String object will not be created.

Example

public class SCPDemo {
   public static void main (String args[]) {
      String s1 = "Tutorials Point";
      String s2 = "Tutorials Point";
      System.out.println("s1 and s2 are string literals:");
      System.out.println(s1 == s2);
      String s3 = new String("Tutorials Point");
      String s4 = new String("Tutorials Point");
      System.out.println("s3 and s4 with new operator:");
      System.out.println(s3 == s4);
   }
}

Output

s1 and s2 are string literals:
true
s3 and s4 with new operator:
false

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