C program to find the nth even number

Given a number N, we need to find the Nth even number.

An even number is a number that is divisible by 2 with a remainder of zero. For example, 2, 4, 6, 8, 10, etc.

If we look closely at lists of even numbers, we can also represent them as

2*1=2, 2*2=4, 2*3=6, 2*4=8,. ..2*N.

So, to solve this problem, we can simply multiply the number N by 2 so that the result is a number that is divisible by 2, i.e. an even number.

Example

Input: n = 4
Output: 8
The first 4 even numbers will be 2, 4, 6, 8, ..

Input: n = 10
Output: 20

Algorithm

START
   STEP 1-> DECLARE AND SET n AS 10
   STEP 2-> PRINT n*2 NUMBER
STOP

Example

#include <stdio.h>
int main(int argc, char const *argv[]){
   int n = 10;
   printf("Nth even will be:%d", n*2);
   return 0;
}

Output

Nth even will be:20

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