JavaScript program to find the maximum number of consecutive 0's placed at the beginning and end of an arbitrary loop in a binary string

We will write a JavaScript program to find the maximum number of zeros placed consecutively at the beginning and end of any loop of a binary string. Our program will take a binary string as input and return the maximum number of zeros placed at the beginning and end in any rotation of the given string. To solve this problem, we will use string manipulation techniques to manipulate the input string and find the desired output.

In the next step, we will rotate the input string and count the number of zeros at the beginning and end of the rotated string. We will continue to rotate the string until we reach the original input string again and keep track of the maximum number of zeros placed at the beginning and end during all rotations.

Finally, we will return the maximum number of zeros as the output of the program. The program will be very efficient and will run in linear time complexity, making it suitable for solving this problem even for large inputs.

method

To find the maximum number of zeros placed consecutively at the beginning and end of any rotation of a binary string, follow these steps -

• First, the original binary string is concatenated with itself to form a new string.

• Next, use a loop to generate all possible rotations of the binary string by moving one character from the beginning to the end of the new string on each iteration.

• For each rotation, find the number of zeros placed consecutively at the beginning and end of the string.

• Store the largest number of zeros found so far in a variable.

• Repeat steps 3 and 4 until all rotations have been processed.

• The final value stored in the variable is the maximum number of zeros placed consecutively at the beginning and end in any loop of a binary string.

Example

Below is an example of a JavaScript program that finds the maximum number of zeros placed consecutively at the beginning and end of any rotation of a binary string -

function maxZeros(binaryString) {
   
   // Store the number of zeros in the original binary string
   let originalZeros = 0;
   while (binaryString[originalZeros] === "0") {
      originalZeros++;
   }
   
   // Store the number of zeros in each rotation of the binary string
   let maxZeros = originalZeros;
   let rotatedZeros = originalZeros;
   for (let i = 1; i < binaryString.length; i++) {
      if (binaryString[i] === "0") {
         rotatedZeros++;
      } else {
         rotatedZeros = 0;
      }
      maxZeros = Math.max(maxZeros, rotatedZeros);
   }
   
   // Return the maximum number of zeros
   return maxZeros;
}

// Example usage
let binaryString = "0110001111";
let maxZerosCount = maxZeros(binaryString);
console.log("The maximum number of zeros is: " + maxZerosCount);

illustrate

• Function maxZeros Takes a binary string as input and returns the maximum number of zeros placed consecutively at the beginning and end of any rotation of that string.

• The first step is to find the number of zeros in the original binary string. This is accomplished using a while loop that continues until a character other than 0 is encountered. The number of zeros is stored in the originalZeros variable.

• The next step is to find the number of zeros in the binary string each time through the loop. To do this, we use a for loop starting at 1 and going up to the length of the binary string. On each iteration of the loop, we check if the current character is 0. If so, we increment the rotatedZeros count. If not, we reset the rotatedZeros count to 0. Finally, we update the maximum number of zeros seen so far by comparing rotatedZeros to maxZeros . >And keep the larger of the two.

• After the loop ends, return the maximum number of zeros.

• Finally, the example usage of the function shows how to call it using a binary string and log the results to the console.

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