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A C program to find numbers that occur an odd number of times in a given array of positive integers. In this array, all numbers appear an even number of times.
Input: arr[] = {5, 7, 8, 8, 5, 8, 8, 7, 7} Output: 7
Use two loops, the outer loop traverses all elements one by one, and the inner loop counts the number of occurrences of the elements traversed by the outer loop.
#include <iostream> using namespace std; int Odd(int arr[], int n){ for (int i = 0; i < n; i++) { int ctr = 0; for (int j = 0; j < n; j++) { if (arr[i] == arr[j]) ctr++; } if (ctr % 2 != 0) return arr[i]; } return -1; } int main() { int arr[] = {5, 7, 8, 8, 5, 8, 8, 7, 7}; int n = 9; cout <<Odd(arr, n); return 0; }
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