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C program to find cos(x) seriesAug 30, 2023 pm 12:17 PM
cos(x):series:c program:

We give the values ​​of x and n, where x is the angle of cos and n is the number of terms in the series of cos(x).

For Cos(x) h3>

Cos(x) is a trigonometric function used to calculate the value of the x angle.

C program to find cos(x) series

Formula

$$\cos (x) = \displaystyle\sum\limits_{k=0} ^\infty \frac{(-1 )^{k}}{(2k!)}x^{2k}$$

For Cos(x) series

Cos( x) = 1 – (x*2 / 2!) (x*4 / 4!) – (x*6 / 6!) (x*8 / 8!)……

Example

Input-: x = 10, n = 3
Output-: 0.984804
Input-: x = 8, n = 2
Output-: 0.990266

In the following program The method used is as follows -

  • Enter the values ​​of x and n
  • Apply the calculation formula of cos(x) series
  • Print the result as all levels Sum of numbers

Algorithm

Start
Step 1 Declare and initialize const double PI = 3.142
Step 2 In function double series_sum(double x, int n)
   Set x = x * (PI / 180.0)
Set result = 1
Set s = 1, fact = 1, pow = 1
    Loop For i = 1 and i < 5 and i++
        Set s = s * -1
        Set fact = fact * (2 * i - 1) * (2 * i)
        Set pow = pow * x * x
        Set result = result + s * pow / fact
     End Loop
    Return result
Step 3 In function int main() s
    Declare and set x = 10
Declare and set n = 3
    Print series_sum(x, n)  
Stop

Example

#include <stdio.h>
const double PI = 3.142;
//will return the sum of cos(x)
double series_sum(double x, int n) {
    x = x * (PI / 180.0);
    double result = 1;
    double s = 1, fact = 1, pow = 1;
    for (int i = 1; i < 5; i++) {
        s = s * -1;
        fact = fact * (2 * i - 1) * (2 * i);
        pow = pow * x * x;
        result = result + s * pow / fact;
    }
    return result;
}
//main function
int main() {
    float x = 10;
    int n = 3;
    printf("%lf</p><p>", series_sum(x, n));  
    return 0;
}

Output

X=10; n=30.984804
X=13; n=80.974363
X=8; n=2 0.990266

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