C program to find array type entered by user

Question

Write a C program to find the array type that needs to be checked to determine whether the elements in a given array are even or odd, or both have.

Solution

The user needs to input an integer array and then display the type of the array.

Example 1 − Input: 5 3 1, output: odd array.

Example 2 − Input: 2 4 6 8, output: even array.

Example 3 − Input: 1 2 3 4 5, output: mixed array.

Algorithm

Refer to the algorithm given below to find the array type entered by the user.

Step 1 − Read the size of the array at runtime.

Step 2 − Enter the array elements.

Step 3 − If all elements of the array are odd, print "odd".

Step 4 − If all elements of the array are even numbers, print "even".

Step 5 − Otherwise, print "Mixed".

Example

The following is a C program to find the array type entered by the user−

Demonstration

#include<stdio.h>
int main(){
   int n;
   printf("enter no of elements:");
   scanf("%d",&n);
   int arr[n];
   int i;
   int odd = 0, even = 0;
   printf("enter the elements into an array:</p><p>");
   for(i = 0; i < n; i++){
      scanf("%d",&arr[i]);
   }
   for(i = 0; i < n; i++){
      if(arr[i] % 2 == 1)
         odd++;
      if(arr[i] % 2 == 0)
         even++;
   }
   if(odd == n)
      printf("Odd Array");
   else if(even == n)
      printf("Even Array");
   else
      printf("Mixed Array");
   return 0;
}

Output

When the above When the program is executed, it produces the following output −

Run 1:
enter no of elements:5
enter the elements into an array:
2 4 8 10 12
Even Array
Run 2:
enter no of elements:5
enter the elements into an array:
1
23
45
16
68
Mixed Array

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