C++ program to find winner of typing game after delay time

Suppose we have five numbers s, v1, v2, t1 and t2. Amal and Bimal are playing a typing game, which they play online. In this game, they will enter a string of length s. Amal enters a character in v1 milliseconds, and Bimal enters a character in v2 milliseconds. Amal's network delay is t1 milliseconds, and Bimal's network delay is t2 milliseconds.

If the connection delay is t milliseconds, the game proceeds as follows:

• After t milliseconds after the game starts, the participant receives the text to enter.

• Then he started typing.

• T milliseconds after he finished inputting all the text, the website received the relevant information.

Whoever finishes first is the winner. If both participants have the same time, it is a tie. We need to find the winner.

So if the input is s = 5; v1 = 1; v2 = 2; t1 = 1; t2 = 2, then the output will be Amal, because Amal's success message arrives in 7 milliseconds, Bimal's Success message arrives within 14 milliseconds. So, Amal wins.

Steps

To solve this problem, we will follow the following steps:

p := (s * v1) + (2 * t1)
q := (s * v2) + (2 * t2)
if p is same as q, then:
   return "Draw"
otherwise when p < q, then:
   return "Amal"
Otherwise
   return "Bimal"

Example

Let us see the below implementation for better understanding −

#include <bits/stdc++.h>
using namespace std;

string solve(int s, int v1, int v2, int t1, int t2) {
   int p = (s * v1) + (2 * t1);
   int q = (s * v2) + (2 * t2);
   if (p == q)
      return "Draw";
   else if (p < q)
      return "Amal";
else
   return "Bimal";
}
int main() {
   int s = 5;
   int v1 = 1;
   int v2 = 2;
   int t1 = 1;
   int t2 = 2;
   cout << solve(s, v1, v2, t1, t2) << endl;
}

Input

5, 1, 2, 1, 2

Output

Amal

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