C program to find the roots of a quadratic equation

In this tutorial, we will be discussing a program to find the roots of the Quadratic equation.

Given a quadratic equation of the form ax2 bx c. Our task is to find the roots x1 and x2 of the given equation.

For this, we are using the deterministic method, in this

D = √b² - 4ac

then the roots of the equation will be

x1 = (-b D)/2a ,and

x2 = (-b - D)/2a

Example

#include<stdio.h>
#include<math.h>
#include<stdlib.h>
//calculating the roots of equation
void calc_roots(int a, int b, int c) {
   if (a == 0) {
      printf("Invalid Equation");
      return;
   }
   int d = b*b - 4*a*c;
   double sqrt_val = sqrt(abs(d));
   if (d > 0) {
      printf("Roots are both real and different </p><p>");
      printf("%f</p><p>%f",(double)(-b + sqrt_val)/(2*a) , (double)(-b - sqrt_val)/(2*a));
   }
   else if (d == 0) {
      printf("Roots are real and same </p><p>");
      printf("%f",-(double)b / (2*a));
   } else {
      printf("Roots are complex </p><p>");
      printf("%f + i%f</p><p>%f - i%f", -(double)b /(2*a),sqrt_val ,-(double)b / (2*a), sqrt_val);
   }
}
int main() {
   int a = 2, b = -5, c = 8;
   calc_roots(a, b, c);
   return 0;
}

输出

Roots are complex
1.250000 + i6.244998
1.250000 - i6.244998

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