In C programming, average numbers in an array

# n elements are stored in the array and the program calculates the average of these numbers. Use different methods.

Input- 1 2 3 4 5 6 7

Output- 4

Description- The sum of the elements of array 1 2 3 4 5 6 7=28

The number of elements in the array=7

Average=28/7=4

There are two methods

Method 1 - Iteration

In this method we will sum and divide the sum of the total number of elements.

Given the size of array arr[] and array n

Input- 1 2 3 4 5 6 7

Output- 4

Explanation- The sum of the elements of the array 1 2 3 4 5 6 7 = 28

The number of elements in the array = 7

Average=28/7=4

Example

#include<iostream>
using namespace std;
int main() {
   int arr[] = { 1, 2, 3, 4, 5, 6, 7 };
   int n=7;
   int sum = 0;
   for (int i=0; i<n; i++) {
      sum += arr[i];
   }
   float average = sum/n;
   cout << average;
   return 0;
}

Method 2 - Recursive

The idea is to pass the element index as an additional parameter and calculate the sum recursively. After calculating the sum, divide the sum by n.

Given the array arr[], the size of the array n and the initial index i

Input- 1 2 3 4 5

Output - 3

Explanation- The sum of array elements 1 2 3 4 5= 15

The number of elements in the array=5

average =15/5=3

Example

#include <iostream>
using namespace std;
int avg(int arr[], int i, int n) {
   if (i == n-1) {
      return arr[i];
   }
   if (i == 0) {
      return ((arr[i] + avg(arr, i+1, n))/n);
   }
   return (arr[i] + avg(arr, i+1, n));
}
int main() {
   int arr[] = {1, 2, 3, 4, 5};
   int n = 5;
   cout << avg(arr,0, n) << endl;
   return 0;
}

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